2 years ago

Convert the value of g=9.8m/s^2 into km/hr^2

Physics

1 answer:

jek_recluse [69]2 years ago

8 0

Answer:

35.28km/hr

Explanation:

You might be interested in

A parallel-plate capacitor is formed from two 2.7 cm -diameter electrodes spaced 1.4 mm apart. The electric field strength insid

Andre45 [30]

Answer:

The potential difference between the plates is $8.4\times10^{3}\ V$

Explanation:

Given that,

Distance = 1.4 mm

Electric field strength $E= 6.0\times10^{6}\ N/C$

Let the potential difference is V.

We need to calculate the potential difference between the plates

Using formula of electric field

$E=\dfrac{V}{d}$

$V=Ed$

Where, V = potential

d = distance

Put the value into the formula

$V=6.0\times10^{6}\times1.4\times10^{-3}$

$V=8.4\times10^{3}\ V$

Hence, The potential difference between the plates is $8.4\times10^{3}\ V$

3 0

2 years ago

85POINTS ASAP!!!!!!!!!!!!!!

alexgriva [62]

The andwer of tye question is 3O2

6 0

2 years ago

Read 2 more answers

Which is the truest statement? Standing is health-enhancing because it uses energy. Jogging is not a good way tp enhance your he

Setler [38]

A. <span>Standing is health-enhancing because it uses energy.

Because standing can burn a lot of calories.</span>

5 0

2 years ago

What was the greatest discovery by galileo during his inclined-plane experiments?

Sergeeva-Olga [200]

Galileo discovered during his inclined-plane experiments that a ball rolling down an incline and onto a horizontal surface would roll indefinitely.

3 0

3 years ago

Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us

nalin [4]

Answer:

$13 W/m^2$

Explanation:

The apparent brightness follows an inverse square law, therefore we can write:

$I \propto \frac{1}{r^2}$

where I is the apparent brightness and r is the distance from the Sun.

We can also rewrite the law as

$\frac{I_2}{I_1}=\frac{r_1^2}{r_2^2}$ (1)

where in this problem, we have:

$I_1 = 1300 W/m^2$ apparent brightness at a distance $r_1$ , where

$r_1 = 150$ million km

We want to estimate the apparent brightness at $r_2$ , where $r_2$ is ten times $r_1$ , so

$r_2 = 10 r_1$

Re-arranging eq.(1), we find $I_2$ :

$I_2 = \frac{r_1^2}{r_2^2}I_1 = \frac{r_1^2}{(10r_1)^2}(1300)=\frac{1}{100}(1300)=13 W/m^2$

5 0

2 years ago

Convert the value of g=9.8m/s^2 into km/hr^2​

Convert the value of g=9.8m/s^2 into km/hr^2