Answer:
Magnification = 1
Explanation:
given data
radius of curvature r = - 0.983 m
image distance u = - 0.155
solution
we get here first focal length that is
Focal length, f = R/2 ...................1
f = -0.4915 m
we use here formula that is
.................2
put here value and we get
<h3>v = 0.155 m </h3>
so
Magnification will be here as
m = ![- \frac{v}{u}](https://tex.z-dn.net/?f=-%20%5Cfrac%7Bv%7D%7Bu%7D)
m =
<h3>m = 1</h3>
A. True
if cold air is replacing warm air it is a cold front and vice versa.
Answer:
![W_m=183.495N](https://tex.z-dn.net/?f=W_m%3D183.495N)
Explanation:
From the question we are told that:
Weight ![W=248Ibs](https://tex.z-dn.net/?f=W%3D248Ibs)
Mass of Weight ![m= 248*0.453](https://tex.z-dn.net/?f=m%3D%20248%2A0.453)
![m=112.344kg](https://tex.z-dn.net/?f=m%3D112.344kg)
Generally the acceleration due to gravity on the Moon is one-sixth that on Earth.
Therefore
The equation for Weight on Moon is given as
![W_m=m*g/6](https://tex.z-dn.net/?f=W_m%3Dm%2Ag%2F6)
![W_m=122.344*\frac{9.8}{6}](https://tex.z-dn.net/?f=W_m%3D122.344%2A%5Cfrac%7B9.8%7D%7B6%7D)
![W_m=183.495N](https://tex.z-dn.net/?f=W_m%3D183.495N)
- Weight (W) = 110 N
- Acceleration due to gravity (g) = 9.8 m/s^2
- Let the mass of the object be m.
- By using the formula, W = mg, we get,
- 110 N = 9.8 m/s^2 × m
- or, m = 110 N ÷ 9.8 m/s^2
- or, m = 11.2 Kg
<u>Answer:</u>
<em><u>The </u></em><em><u>mass </u></em><em><u>of </u></em><em><u>the </u></em><em><u>object </u></em><em><u>is </u></em><em><u>1</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u> </u></em><em><u>Kg.</u></em>
Hope you could get an idea from here.
Doubt clarification - use comment section.