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snow_lady [41]
3 years ago
7

Note the mass of copper(1) oxide formula unit 143.091 what is the mass of 8.250 moles of Cu2O

Chemistry
1 answer:
baherus [9]3 years ago
6 0

Answer:

The mass of 8.250 moles of Cu2O is 1180.5g

Explanation:

HOW TO CALCULATE MASS OF A SUBSTANCE:

  • The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

Mass (g) = no. of moles (mol) × molar mass (g/mol)

  • Molar mass of copper (I) oxide (Cu2O) = 63.5(2) + 16 = 143.09 g/mol

Mass of Cu2O = 8.250 mol × 143.09 g/mol

Mass of Cu2O = 1180.5 g

Therefore, the mass of 8.250 moles of Cu2O is 1180.5 g.

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Nadusha1986 [10]

Answer:

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>

Explanation:

given amount of salt at time t is A(t)

initial amount of salt =300 gm =0.3kg

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rate of salt inflow =5*0.4= 2 kg/min

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rate of change of salt at time t , dA/dt= rate of salt inflow- ratew of salt outflow

dA/dt=2-(A/40)\\\\dA=2dt-(A/40)dt\\\\dA+(A/40)dt=2dt

integrating factor

=e^{\int\limits (1/40) \, dt}

integrating factor =e^{(1/40)t}

multiply on both sides by  =e^{(1/40)t}

dAe^{(1/40)t}+(A/40)e^{(1/40)t} dt =2e^{(1/40)t}t\\\\(Ae^{(1/40)t})=2e^{(1/40)t}t

integrate on both sides

\int\limits(Ae^{(1/40)t})=\int\limits2e^{(1/40)t}dt\\\\(Ae^{(1/40)t})=2*40e^{(1/40)t}+C\\\\A=80+(C/e^{(1/40)t})\\\\A(0)=0.3\\\\0.3=80+(C/e^{(1/40)t}^*^0)\\\\0.3=80+(C/1)\\\\C=0.3-80\\\\C=-79.7\\\\A(t)=80-(79.7/e^{(1/40)t})

b)

after long period of time means t - > ∞

{t \to \infty}\\\\ \lim_{t \to \infty} A_t \\\\ \lim_{t \to \infty} (80)-(79/{e^{(1/40)t}}\\\\=80-(0)\\\\=80

<h3>Therefore, after long period of time 80kg of salt will remain in tank</h3>
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