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4 years ago

Sodium combines with water to produce sodium hydroxide and hydrogen gas which word equation represents this violent reaction

Chemistry

2 answers:

a_sh-v [17]4 years ago

8 0

Answer:

B). Soduim + water = sodium hydroxide + hydrogen

Explanation:

2Na + 2H₂O → 2NaOH + H₂

Sodium reacts violently with water to produce sodium hydroxide and releasing hydrogen gas during the process. This type of reaction is typical of group 1 metals.

This reaction is used to produce hydroxide of group 1 metals.

Deffense [45]4 years ago

5 0

2Na + 2HOH = 2NaOH + H₂↑

Na-sodium

HOH-water

NaOH-sodium hydroxide

H₂-hydrogen gas

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Answer:

3.61 * 10 ²⁴atoms.

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

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From the question ,

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1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction

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$H_{comb}=-4406kJ/mol$

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

$H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}$

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

$H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol$

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