Answer:
The circular turning of roads
Explanation:
please mark brainliest
Op here is another problem exactly like that. Just plug in your variables instead. And remember, time is never negative.
Assume the snow is uniform, and horizontal.
Given:
coefficient of kinetic friction = 0.10 = muK
weight of sled = 48 N
weight of rider = 660 N
normal force on of sled with rider = 48+660 N = 708 N = N
Force required to maintain a uniform speed
= coefficient of kinetic friction * normal force
= muK * N
= 0.10 * 708 N
=70.8 N
Note: it takes more than 70.8 N to start the sled in motion, because static friction is in general greater than kinetic friction.
The answer is the first one
I think it’s, its direction would reinforce the original movement
