Answer:
The velocity of the first block is 1.15m/s while of the second block 2.56m/s.
Explanation:
Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.
Therefore, from conservation of momentum
and from conservation of energy
Thus, we have two equations and two unknowns
which has solutions
and
Since the blocks cannot pass through each other, the 0.5kg block cannot have 
(moves to the left) while the 0.4 kg block has 
(moves to the right); therefore, we take the first solution for the velocities:
.
Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.
... power p supplied to a resistor whose resistance is r when it is known that it has a voltage δv across ... supplied to a resistor whose resistance
Power = (work or energy) / (time)
100 W = (energy) / (20 sec)
Energy = 2,000 watt-sec
<em>Energy = 2,000 J</em>
To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,
Here,
= Angle between areal vector and magnetic field direction.
According to Faraday's law, induced emf in the loop is,
At time 
, Induced emf is,
Therefore the magnitude of the induced emf is 10.9V
