Ask question

Ask question

All categories

3 years ago

11

Two carts with masses of 4.32 kg and 2.66 kg move toward each other on a frictionless track with speeds of 4.86 m/s and 3.93 m/s

respectively. The carts stick together after colliding head-on. Find the final speed.

1 answer:

ollegr [7]3 years ago

6 0

Answer:

m¹v¹+m¹v¹=(m¹+m²)v

4.32*4.86+2.66*3.93=(3.96+4.86)v

v=31.44/8.82

=3.56

You might be interested in

Please help with 4 and 5, thank you :)

allochka39001 [22]

Answer: #4

Sally is faster.

Explanation:

If you multiply Sallies it is going to be less than Jessica's.

6 0

3 years ago

A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th

lana [24]

Answer:

a. $\displaystyle k_o=1350\ J$

b. $\displaystyle k_1=0\ J$

c. $\Delta k=-1350\ J$

d. $W=-1350\ J$

e. $F=-675\ N$

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

$\Delta k=k_1-k_0$

Knowing that

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The work done by the force who caused the change of velocity (acceleration) is

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

If we know the distance x traveled by the object, the work can also be calculated by

$W=F.x$

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

$\displaystyle k_o=\frac{mv_0^2}{2}$

$\displaystyle k_o=\frac{(75)6^2}{2}$

$\boxed{\displaystyle k_o=1350\ J}$

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

$\displaystyle k_1=\frac{(75)0^2}{2}$

$\boxed{\displaystyle k_1=0\ J}$

c. The change of kinetic energy is

$\Delta k=k_1-k_0=0\ J-1350\ J$

$\boxed{\Delta k=-1350\ J}$

d. The work done by friction to stop the player is

$W=\Delta k=k_1-k_0$

$\boxed{W=-1350\ J}$

e. We compute the force of friction by using

$W=F.x$

and solving for x

$\displaystyle F=\frac{W}{x}$

$\displaystyle F=\frac{-1350\ J}{2\ m}$

$\boxed{F=-675\ N}$

The negative sign indicates the force is against movement

6 0

3 years ago

Describe the effect of speed on voltage

11Alexandr11 [23.1K]

Answer:

Speed has no effect on voltage.

Explanation:

The voltage of the battery in your car is always 12 to 13.5 volts. It makes no difference whether the car is home in the garage or zooming down the interstate.

6 0

3 years ago

What is the mathematical equation for calculating the internal energy of a<br> diatomic gas? <br> -

Mariulka [41]

Answer:

U = 5/2 NkT.

Explanation:

A diatomic molecule = H₂, O₂, N₂ .....etc

A diatomic molecule has 5 degrees of freedom.

3 transnational modes = x, y, z
2 rotational modes = ωx , ωy

So, the internal energy for diatomic gases is :

U = 5/2 NkT.

7 0

3 years ago

In which part of the EM spectrum do you see the colors red, orange, yellow, green, blue, indigo, and violet (ROYGBIV);

Lilit [14]

Answer:

gamma rays

Explanation:

hope it helps

7 0

3 years ago