Answer:
The velocity of water at the bottom, ![v_{b} = 28.63 m/s](https://tex.z-dn.net/?f=v_%7Bb%7D%20%3D%2028.63%20m%2Fs)
Given:
Height of water in the tank, h = 12.8 m
Gauge pressure of water, ![P_{gauge} = 2.90 atm](https://tex.z-dn.net/?f=P_%7Bgauge%7D%20%3D%202.90%20atm)
Solution:
Now,
Atmospheric pressue, ![P_{atm} = 1 atm = 1.01\tiems 10^{5} Pa](https://tex.z-dn.net/?f=P_%7Batm%7D%20%3D%201%20atm%20%3D%201.01%5Ctiems%2010%5E%7B5%7D%20Pa)
At the top, the absolute pressure, ![P_{t} = P_{gauge} + P_{atm} = 2.90 + 1 = 3.90 atm = 3.94\times 10^{5} Pa](https://tex.z-dn.net/?f=P_%7Bt%7D%20%3D%20P_%7Bgauge%7D%20%2B%20P_%7Batm%7D%20%3D%202.90%20%2B%201%20%3D%203.90%20atm%20%3D%203.94%5Ctimes%2010%5E%7B5%7D%20Pa)
Now, the pressure at the bottom will be equal to the atmopheric pressure, ![P_{b} = 1 atm = 1.01\times 10^{5} Pa](https://tex.z-dn.net/?f=P_%7Bb%7D%20%3D%201%20atm%20%3D%201.01%5Ctimes%2010%5E%7B5%7D%20Pa)
The velocity at the top,
, l;et the bottom velocity, be
.
Now, by Bernoulli's eqn:
![P_{t} + \frac{1}{2}\rho v_{t}^{2} + \rho g h_{t} = P_{b} + \frac{1}{2}\rho v_{b}^{2} + \rho g h_{b}](https://tex.z-dn.net/?f=P_%7Bt%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_%7Bt%7D%5E%7B2%7D%20%2B%20%5Crho%20g%20h_%7Bt%7D%20%3D%20P_%7Bb%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Crho%20v_%7Bb%7D%5E%7B2%7D%20%2B%20%5Crho%20g%20h_%7Bb%7D%20)
where
![h_{t} - h_{b} = 12.8 m](https://tex.z-dn.net/?f=h_%7Bt%7D%20-%20%20h_%7Bb%7D%20%3D%2012.8%20m)
Density of sea water, ![\rho = 1030 kg/m^{3}](https://tex.z-dn.net/?f=%5Crho%20%3D%201030%20kg%2Fm%5E%7B3%7D)
![\sqrt{\frac{2(P_{t} - P_{b} + \rho g(h_{t} - h_{b}))}{\rho}} = v_{b}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2%28P_%7Bt%7D%20-%20P_%7Bb%7D%20%2B%20%5Crho%20g%28h_%7Bt%7D%20-%20h_%7Bb%7D%29%29%7D%7B%5Crho%7D%7D%20%3D%20%20v_%7Bb%7D)
![\sqrt{\frac{2(3.94\times 10^{5} - 1.01\times 10^{5} + 1030\times 9.8\times 12.8}{1030}} = v_{b}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2%283.94%5Ctimes%2010%5E%7B5%7D%20-%201.01%5Ctimes%2010%5E%7B5%7D%20%2B%201030%5Ctimes%209.8%5Ctimes%2012.8%7D%7B1030%7D%7D%20%3D%20%20v_%7Bb%7D)
![v_{b} = 28.63 m/s](https://tex.z-dn.net/?f=v_%7Bb%7D%20%3D%2028.63%20m%2Fs)
Answer and Explanation:
1. Evidence can be observed that light is energy-consuming because the liquid crystal sheet sets the temperature and gets warmer. With this, we can affirm that the light energy, moved the liquid crystal sheet molecules, making them when they move generate heat.
2. The evidence that light loads energy can be seen through the movement of the toy. This is because the light states that there was energy received, which will make all the gear of the toy work and move it.
Answer:
The answer is explained below.
Explanation:
The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.
Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.
Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation from fourth level to ground level directly.
The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.
Upper mantle
The theory of the plate tectonics uses the convection cells in the upper mantle layer as the foundation for the movement of the continents.
To put it simple the process is explained like the convection cells create a lot of pressure, that pressure, supported by the high temperatures and magma, influence the crust above, and manage to crack it on certain places. As the crust cracks, it becomes a separate entity, and under the enormous force from bellow it slowly moves into a particular direction, and that is actually the movement of the tectonic plates.