The light beacon of a lighthouse is situated a distance 2.00 km from a long, straight shoreline (shortest distance to the shorel
ine). The light rotates at a rate of 3.00 rev/minute. At a certain time, the illuminated spot on the shoreline is 4.00 km from the lighthouse. How fast is the illuminated spot moving at that point?
1 answer:
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Answer:
∆h = 0.071 m
Explanation:
I rename angle (θ) = angle(α)
First we are going to write two important equations to solve this problem :
Vy(t) and y(t)
We start by decomposing the speed in the direction ''y''
Vy in this problem will follow this equation =
where g is the gravity acceleration
This is equation (1)
For Y(t) :
We suppose yi = 0
This is equation (2)
We need the time in which Vy = 0 m/s so we use (1)
So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)
2.236 m is the maximum height from the shell (in which Vy=0 m/s)
Let's calculate now the height for t = 0.555 s
The height asked is
∆h = 2.236 m - 2.165 m = 0.071 m
Answer:
<h2>2.22 kPa</h2>Explanation:
The new volume can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>2.22 kPa</h3>Hope this helps you
The block's velocity is determined as 10.03 m/s.
<u>Explanation:</u>
According to work energy theorem, the work done on an object is equal to the change in kinetic energy of the object.
So, work done = Kinetic energy
Thus, the velocity can be determined as
Velocity = 10.03 m/s.
So the block's velocity is determined as 10.03 m/s.