Answer:
=_____________________________________
Explanation:
Answer:
option (c)
Explanation:
90% of the body is submerged in water.
Now it is immersed in an unknown liquid whose density is less than the density of water.
Buoyant force acting on the body depends on the volume immersed, density of liquid and gravity.
As the density of liquid is less than the density of water, so the buoyant force acting on the body by the unknown liquid is less than water. So it is submerged less than 90% in this liquid.
M = mass of the larger fish =5kg
<span>V = velocity of the larger fish =10m/s</span>
<span>m = mass of the smaller fish =2kg</span>
<span>v = velocity of the smaller fish =10m/s
</span>formula=
<span>MV = mv
5kg*10m/s=2kg*10m/s
biggern mass fish has more momentum
hope this helps
</span>
Answer:
The answer to your question is : vf = 15.18 m/s
Explanation:
Data
vo = 24 m/s
d = 120 m
vf = ? when d = 60.0 m
Formula
vf² = vo² + 2ad
For d =100m
a = (vf² - vo²) / 2d
a = (0 -24²) / 2(100)
a = -576/200
a = 2.88 m/s²
Now, when d = 60
vf² = (24)² - 2(2.88)(60)
vf² = 576 - 345.6
vf² = 230.4
vf = 15.18 m/s
