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vredina [299]
2 years ago
10

Ditto sound waves espace room answers please I need this urgently ​

Physics
1 answer:
lord [1]2 years ago
6 0

The actual question should be did the sound waves escape room?

Yes they can escape the room

  • Sound always needs a medium to travel through
  • If you close the room form all where that even air can't go outside you will be able to hear no sound coming from room .
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Shown here are astronomical objects located at different distances from Earth. Rank the objects based on their distances from Ea
nevsk [136]

Answer: star on far side of Andromeda Galaxy- star on near side of Andromeda Galaxy- star on far side of Milky Way Galaxy- star near center of Milky Way Galaxy- Orion Nebula- Alpha Centauri- Pluto-The Sun

Explanation:

Andromeda is the nearest spiral galaxy to our Milky way galaxy. The star on the far side of the Andromeda galaxy would be farthest from Earth. Then, the star at the near side of the Andromeda galaxy.

The Earth along with the Sun and other planets are located in the Orion arm of the Milky way. It is about 8 kpc from the center of the Milky way. Thus, the next farthest astronomical object would be the star on the far side of the milky way and then a star near the center of the Milky way galaxy.

Orion Nebula is 1344 ly away from Earth. Alpha centauri is 4.36 ly away from earth. Pluto is about 28 AU away from Earth and Sun is 1 AU distance away.

4 0
3 years ago
Cart A, with a mass of 0.20 kg, travels on a horizontal air trackat 3.0m/s and hits cart B, which has a mass of 0.40 kg and is i
inysia [295]

Answer:

\large \boxed{\text{C. 2.3 m/s}}

Explanation:

Data:

m_{\text{A} } = \text{0.20 kg};\,v_{\text{Ai}} = \text{3.0 m/s}\\m_{\text{B} } = \text{0.40 kg};\,v_{\text{Bi}} = \text{2.0 m/s}\\

Calculation:

This is a perfectly inelastic collision.  The two carts stick together after the collision and move with a common final velocity.

The conservation of momentum equation is

\begin{array}{rcl}m_{\text{A}}v_{\text{Ai}} +m_{\text{B}} v_{\text{Bi}}&=&(m_{\text{A}}  + m_{\text{B}})v_{\text{f}}\\0.20\times 3.0 + 0.40\times 2.0 & = & (0.20 + 0.40)v_{\text{f}}\\0.60 + 0.80 & = & 0.60v_{\text{f}}\\1.40 & = & 0.60v_{\text{f}}\\v_{\text{f}}&=& \dfrac{1.40}{0.60}\\\\& = & \textbf{2.3 m/s}\\\end{array}\\\text{The centre of mass has a velocity of $\large \boxed{\textbf{2.3 m/s}}$}

3 0
3 years ago
What term is a force that can slow momentum <br><br> A. mass<br><br> B. friction
jenyasd209 [6]
Your answer is friction. Friction between to object slows the object down.
3 0
3 years ago
Read 2 more answers
If the scaled-up man now stands on one leg, what fraction of the tensile strength is the stress on the femur?.
Oksanka [162]

The fraction of the tensile strength which is the stress on the femur is 1.4%.

<h3>What is Tensile strength?</h3>

This is defined as the amount of load or stress that a material can handle before it stretches and breaks.

The femur which is located in the thigh is the largest bone in the body and it exerts a fraction of 1.4% tensile strength through the stress encountered on the femur when the man stands with one leg.

Read more about Tensile strength here brainly.com/question/25748369

5 0
2 years ago
A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be
nirvana33 [79]

Answer:

Work done, W = 19.6 J

Explanation:

It is given that,

Mass of the block, m = 5 kg

Speed of the block, v = 10 m/s

The coefficient of kinetic friction between the block and the rough section is 0.2

Distance covered by the block, d = 2 m

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

W=\mu_kmgd

W=0.2\times 5\times 9.8\times 2

W = 19.6 J

So, the change in the kinetic energy of the block as it passes through the rough section is 19.6 J. Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
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