A chemical property<span> is any of a material's </span>properties<span> that becomes evident during, or after, a </span>chemical<span> reaction; that is, any quality that can be established only by changing a substance's </span>chemical<span> identity.</span>
Answer:
Depending on the volume, it could be a supersaturated solution.
Explanation:
Answer:
4.13 moles of Fe.
Explanation:
Given data:
Moles of iron produced = ?
Moles of Fe₂O₃ = 3.5 mol
Moles of CO = 6.2 mol
Solution:
Chemical equation:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Now we will compare the moles of iron with CO and Fe₂O₃.
Fe₂O₃ : Fe
1 : 2
3.5 : 2/1×3.5 = 7 mol
CO : Fe
3 : 2
6.2 : 2/3×6.2 = 4.13 mol
The number of moles of iron produced by CO are less it will limiting reactant.
Thus, moles of iron formed in given reaction are 4.13 moles.
Answer:Crop rotation also helps to battle against the forces of erosion. Rotating crops helps to improve soil stability by alternating between crops with deep roots and those with shallow roots. Pests are also deterred by eliminating their food source on a regular basis.
Crop rotation is the practice of growing a series of dissimilar or different types of crops in the same area in sequenced seasons. It is done so that the soil of farms is not used for only one set of nutrients. It helps in reducing soil erosion and increases soil fertility and crop yield.
The goal of crop rotation is to reduce the amount of the pest population present in the soil. Some pathogens that cause diseases survive in the soil from year to year in one form or the other, usually as sclerotia, spores, or hyphae. Rotating to non-host crops prevents the buildup of large populations of pathogens.
Explanation: the answer would be 4
Increases soil fertility. ...
Increases crop yield. ...
Increase in soil nutrients. ...
Reduces soil erosion. ...
Limits concentration of pests and diseases. ...
Reduces the stress of weeds. ...
Improves the soil structure. ...
Reduces pollution.
<em>c</em> = 1.14 mol/L; <em>b</em> = 1.03 mol/kg
<em>Molar concentration
</em>
Assume you have 1 L solution.
Mass of solution = 1000 mL solution × (1.19 g solution/1 mL solution)
= 1190 g solution
Mass of NaHCO3 = 1190 g solution × (7.06 g NaHCO3/100 g solution)
= 84.01 g NaHCO3
Moles NaHCO3 = 84.01 g NaHCO3 × (1 mol NaHCO3/74.01 g NaHCO3)
= 1.14 mol NaHCO3
<em>c</em> = 1.14 mol/1 L = 1.14 mol/L
<em>Molal concentration</em>
Mass of water = 1190 g – 84.01 g = 1106 g = 1.106 kg
<em>b</em> = 1.14 mol/1.106 kg = 1.03 mol/kg
