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Nikitich [7]
3 years ago
8

Consider light of wavelengths 400 nm (UV), 550 nm (green, visible), and 900 nm (infrared). What is the energy associated with a

400 nm (UV) photon, a 550 nm (green, visible) photon, and a 900 nm (infrared) photon?
Physics
1 answer:
allsm [11]3 years ago
8 0

Answer:

Energy of UV light =4.95\times 10^{-19}j

Energy of green light =3.6\times 10^{-19}j

Energy of infrared light =2.2\times 10^{-19}j

Explanation:

We have given the wavelength of UV light = 400 nm =400\times 10^{-9}m , wavelength of green light = 550 nm and wavelength of infrared = 900 nm

Speed of light c=3\times 10^8m/sec

Plank's constant h=6.6\times 10^{-34}

Energy of the signal is given by E=h\nu =h\frac{c}{\lambda }

So energy of UV light E=\frac{6.6\times 10^{-34}\times3\times 10^8}{400\times 10^{-9}}=4.95\times 10^{-19}j

Energy of green light E=\frac{6.6\times 10^{-34}\times3\times 10^8}{550\times 10^{-9}}=3.6\times 10^{-19}j

Energy of infrared light E=\frac{6.6\times 10^{-34}\times3\times 10^8}{900\times 10^{-9}}=2.2\times 10^{-19}j

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