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love history [14]

2 years ago

13

Match the descriptions with the graphs !

1 answer:

noname [10]2 years ago

8 0

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

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Balance the following equation Fe203+HCL fecl3+H20

Arturiano [62]

Balanced equation:
6 HCl + Fe2O3 = 2 FeCl3 + 3 H2O

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3 years ago

A particle hangs from a spring and oscillates with a period of 0.2s.If the mass-spring system remained at rest, by how much woul

photoshop1234 [79]

Answer:

The distance the mass would stretch it is $x = 0.00992948$

The correct option is A

Explanation:

From the question we are told that

The period of the slit is $T = 0.2s$

The acceleration due to gravity is $g =9.8 m/s^2$

Generally the period is mathematically represented as

$T = 2 \pi \sqrt{\frac{m}{k} }$

Whee m is the particle and k is the spring constant

making $\frac{m}{k}$ the subject

$\frac{m}{k} = [\frac{T}{2 \pi} ]^2$

The weight on the particle is related to the force stretching the spring by this mathematical relation

$W = F_s$

$mg = kx$

where x is the length by which the spring is stretched

$\frac{m}{k} = \frac{x}{g}$

Substituting the equation above for $\frac{m}{k}$

$[\frac{T}{2 \pi} ]^2 = \frac{x}{g}$

making x the subject

$x = g [\frac{T}{2 \pi} ]$

Substituting the value

$x = 9.8 * [\frac{0.2}{2 * 3.142} ]^2$

$x = 0.00992948$

6 0

3 years ago

Read 2 more answers

What is the acceleration of a rocket if 200 Newtons are applied to its 5.5 kg

snow_tiger [21]

Given
Force=200N
Mass=5.5kg

F=ma
a=F/m=200/5.5=38.18metre per second

7 0

3 years ago

A trolley has a mass of 1.2 kg and a speed of 4.5 m/s. The trolley crashes into a stationary trolley of mass 0.8 kg. On impact t

attashe74 [19]

(a) The momentum of the first trolley is 5.4 kgm/s

(b) The velocity of the trolleys after impact is 2.7m/s

<u>Explanation:</u>

Given:

Mass, m₁ = 1.2kg

Velocity, v₁ = 4.5m/s

Mass, m₂ = 0.8kg

v₂ = 0

(a) Momentum of the trolley before impact, p

We know:

Momentum = mass X velocity

p = 1.2 X 4.5

p = 5.4 kgm/s

Therefore, the momentum of the first trolley is 5.4 kgm/s

(b) Speed of the trolleys after impact, v = ?

During collision, the momentum is conserved.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

(1.2 X 4.5) + (0.8 X 0) = (1.2 +0.8) X v

5.4 + 0 = 2v

v = 2.7m/s

Therefore, the velocity of the trolleys after impact is 2.7m/s

8 0

3 years ago

Which of the following statements are true of thermal energy and kinetic

Elis [28]

Answer:

a

all the molecules or atoms in motion has kinetic energy

4 0

1 year ago