Answer:
Explanation:
[ H₃O⁺¹] = 4.8 x 10⁻¹¹ mol / l
H₃O⁺¹ = H₂O + H⁺
[ H₃O⁺¹] = [H⁺]
pH = -log[H⁺]
= -log[ 4.8 x 10⁻¹¹]
= -log 4.8 + 11
= - 0 .68 + 11
= 10.32
5.54 x 10⁻³ M
<h3>
Further explanation</h3>
Given:
Neutralization reaction between:
- 25.00 ml of Ba(OH)₂
- 18.45 ml of 0.015 M HCl
Question:
What is the molarity of the Ba(OH)₂ solution?
The Process:
Let us say the molarity of the Ba (OH)₂ solution as x M.
Step-1: prepare moles for each reagent



Step-2: neutralization
We use the ICE table to see how neutralization occurs between acid and base.
Balanced reaction:

Initial: 25x 0.277 - -
Change: - ¹/₂ · (0.277) -0.277 +¹/₂ · (0.277) +0.277
Equlibrium: - - +¹/₂ · (0.277) +0.277
- Neutralization causes no excess of hydrogen or hydroxide ions in solution. In the end, the number of acid and base reactions is balanced. In other words, the two reagents have run out with nothing left.
- HCl acts as a limiting reagent.
Step-3: calculate the molarity of the Ba(OH)₂ solution.
We consider Ba (OH) from the initial, change, and equilibrium stages.





Thus, the molarity of the Ba(OH)₂ solution is 5.54 x 10⁻³ M.
_ _ _ _ _ _ _ _ _ _
Alternative Steps
- Valence of base = the number of OH⁻ ions
- Valence of acid = the number of H⁺ ions
Neutralization: 


Thus the same results were obtained. The molarity of Ba (OH) ₂ solution is 5.54 x 10⁻³ M.
<h3>
Learn more</h3>
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Three hydrogen will provide three valence electrons and nitrogen has five valence electrons all in all they 8 valence electron
**
H*«N«*H=NH3
«*
H
The symbols in the parenthesis represents state of that matter.( l )represents liquid, (g) represents gas, (s) represents solid and (aq) represents aqueous. Hope this helps.
According to the number of bonds present in a methane molecule, in the combustion of one methane molecule, four C-H covalent bonds are broken.
<h3>How many bonds are broken in a methane molecule?</h3>
A methane molecule is composed of four atoms of hydrogen and one atom carbon.
The formula of a methane molecule is CH4.
The bonds present in methane molecule are four C-H covalent bonds.
Therefore, in the combustion of one methane molecule, four C-H covalent bonds are broken.
Learn more about about methane at: brainly.com/question/25419929