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tester [92]
4 years ago
15

What happens if more product is added to a system at equilibrium apex?

Chemistry
1 answer:
serg [7]4 years ago
6 0
According to Le Chatelier's Principle," If a system (reaction) at equilibrium is subjected to any external stress, either by changing pressure, temperature or concentration of reactants or products, the system will adjust itself in such a way that the effect is minimized".

So, when more product is added to reaction at equilibrium, the equilibrium will shift in backward direction in order to minimize the effect of concentration of product.

Result:
           With the addition of product, the rate of backward reaction will increase resulting in increasing the concentration of reactants.
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Study the following two reactions. Select all that apply.
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Its B and D
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3 years ago
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Consider a gray and opaque surface at 0°c in an environment at 25°C. The surface has an emissivity of 0.8. if the radiation in
valina [46]

The radiosity of this surface is 299.95W/m².

<h3>Calculation :</h3>

Given, € 0.8

Ta=0°C 273K

For opaque body., T = 0

a+ p = 1

€ = a (Kirchoff's Law)

p = (1-E)

Radiosity = leaving energy from the surface

= px 240 +€σT4

= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)

= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)

= 299.95W/m²

So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².

To know more about Radiosity please click here : brainly.com/question/14937321

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2 years ago
c) What is the pH of the buffer system in part a when 0.030 moles of strong acid are added (without a change in volume)
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Answer:

remain the same

Explanation:

The pH of the buffer system remain the same when 0.030 moles of strong acid are added because buffer system has the property to resist any change in the pH  when acid or base is added to the solution. In buffer system, one molecule is responsible for neutralizing the pH of the solution by giving H+ or OH-.This molecule is known as buffer agent. If more base is added, the molecule provide H+ and when more acid is added to the solution, then the molecule add OH- to the solution.

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