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12345 [234]
3 years ago
15

A balloon filled with helium gas at 1.00 atm occupies 12.9 L. What volume would the balloon occupy in the upper atmosphere, at a

pressure of 0.19 atm and a constant temperature? Enter your answer in the box provided.
Chemistry
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

67,9 L

Explanation:

Boyle's Law indicates that the pressure of a fixed amount of gas at a constant temperature is inversely proportional to the volume of a gas, for a constant amount of gas we can write:

P1V1=P2V2

For the problem:

P1= 1 atm, V1= 12,9 L

P2=0,19 atm, V2=?

Therefore:

V2=P1V1/P2.................... V2=1 atm*12,9L/0,19 atm = 67,9 L

The balloon would occupy a volume of 67,9 L in the upper atmosphere.

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The Lewis dot notation for two atoms is shown.
Iteru [2.4K]

Answer:

Mg donates two electrons to O

Explanation:

Lewis dot notation uses dots and crosses to represent valence electrons on atoms.

Magnesium is a metal and would donate or lose electrons during bonding.

Oxygen is a non metal and would gain electrons during bonding.

The correct option is;

Mg donates two electrons to O

5 0
2 years ago
How many moles are in 400 ml of hydrogen
Nezavi [6.7K]

Answer:

403.176

Explanation:

I hope that the right answer.

8 0
3 years ago
Why does the nitrogen concentration decrease after hydrogen is added? n2(g)+3h2(g)⇌2nh3(g) why does the nitrogen concentration d
Leno4ka [110]

<span>The chemical reaction of a reversible reaction is actually governed by Le Chatelier’s principle. It states that when more reactants are introduced into the system, the reaction will proceed forward to create more products. So since Hydrogen is a reactant and Nitrogen is also reactant so adding more Hydrogen makes more products hence reducing the Nitrogen concentration.</span>

3 0
3 years ago
Will mark brainliest​
MArishka [77]

Answer:

D. water

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7 0
2 years ago
A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0
3 years ago
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