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goldfiish [28.3K]
3 years ago
13

Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen

. When Lucille talked about it with a friend, her friend said there might be a problem with Lucille’s respiratory system or circulatory system.
Chemistry
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

They might not be bringing in enough oxygen from the air. It's hard to play soccer if you don't have enough oxygen in your cells. They might not be breaking down starch to make glucose.

Explanation:

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motikmotik

Answer:

CasH52(1) + 38 O2(g) → 25 CO2(g) + 26 H2O(g)

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2 years ago
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What is the mass of the light bulb and paperclips together? a. 250.1 g b. 246.0 g c. 251.0 g d. 205.10 g
ololo11 [35]

251.0 is the correct mass  of the light bulb and paperclips together.

<h3>What is mass ? </h3>

Mass is a physical body's total amount of matter. Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term. The strength of an object's gravitational pull to other bodies is also influenced by its mass. The kilogram serves as the SI's fundamental mass unit.

For a body, mass is constant. Mass can be calculated using the formula: mass = volume density. A mass's weight is a measurement of the gravitational force at work on it. The kilogram is the SI unit of mass.

The mass of the substance will therefore be calculated as follows: MASS OF A SUBSTANCE = VOLUME DENSITY.

So finally we can say that the mass of the light bulb and paperclips together is 250.1g.

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2 years ago
What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capac
Artist 52 [7]

42.34 g of water could be warmed from 21.4°C to 43.4°C  by the pellet dropped inside it

Heat loss by the pellet is equal to the Heat gained by the water.

q_{w} = -q_{p} ….(1)

where, q_{w} is the heat gained by water

q_{p} is the heat loss by pellet

q_{w} = mCΔT

where m = mass of water

C = specific heat capacity of water = 4.184 J/g-°C

ΔT = Increase in temperature

ΔT for water = 43.4 - 21.4 = 22°C

q_{w} = m × 4.184 × 22 …. (2)

Now

q_{p} = H_{c} ×ΔT

where H_{c} = Heat capacity of pellet = 56J/°C

Δ T for pellet = 43.4 - 113 =- 69.6°C

q_{p} = 56 × -69.6 = -3897.6 J

From equation (1) and (2)

-m× 4.184 × 22 =-3897.6

m= 42.34 g

Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.

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What is 736.9x10^5 in standard form
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Answer:

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