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aalyn [17]
4 years ago
8

Using the equation for for Newton's Second law, m=F/a solve the following problem. You have been given an object with a force of

10N and an acceleration of 2 m/s2, what is the mass?
Group of answer choices

1. 8g

2. 3g

3. 20g

4. 5g
Physics
1 answer:
inessss [21]4 years ago
8 0

Answer:

4. 5g

Explanation:

F=ma so, m=Fa. All you have to do is 10/2. Don't be confused by the units. Mass will normally be in grams.

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A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist
7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

P = VI

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}

b) The resistance <em>R</em><em> </em>of the heater is

P = VI = (IR)I = I^2R

where V= IR is our familiar Ohm's Law.

\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}

R = 110.8\:Ω

8 0
3 years ago
We can study how galaxies evolve because ________. We can study how galaxies evolve because ________. we are really smart astron
professor190 [17]

Answer:the farther away we look, the further back in time we see.

8 0
4 years ago
Feminine of mouse <br><br>please let me know​
yaroslaw [1]

Answer:

a Doe

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(hope that helped)

5 0
3 years ago
The Doppler effect using ultrasonic waves of frequency 2.25 × 106 Hz is used to monitor the heartbeat of a fetus. A (maximum) be
miss Akunina [59]

Answer:

v = 2.88 \times 10^7 m/s

Explanation:

As per Doppler's effect we know that the frequency of the sound that is observed by the detector is the reflected sound

This reflected sound is given as

f' = f (\frac{v - v_h}{v + v_h})

f' = 2.25\times 10^6(\frac{v - 1540}{v + 1540})

so we know that the beat frequency is

\Delta f = 240 Hz

so we will have

f - f' = \Delta f

2.25 \times 10^6 - 2.25\times 10^6(\frac{v - 1540}{v + 1540}) = 240

1 - (\frac{v - 1540}{v + 1540}) = 1.07 \times 10^{-4}

so we have

0.99989 = (\frac{v - 1540}{v + 1540})

1.99989\times 1540 = 1.067 \times 10^{-4} v

v = 2.88 \times 10^7 m/s

4 0
4 years ago
What is the velocity of an electron that has a de Broglie wavelength approximately the length of a chemical bond? Assume this le
melomori [17]

Answer : The velocity of an electron is, 6.1\times 10^{6}m/s

Explanation :

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{p}

and,

p=mv

where,  

p = momentum, m = mass, v = velocity

So, the formula will be:

\lambda=\frac{h}{mv}       .............(1)

where,

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength  = 1.2\times 10^{-10}m

m = mass  of electron = 9.11\times 10^{-31}kg

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}

v=6.1\times 10^{6}m/s

Thus, the velocity of an electron is, 6.1\times 10^{6}m/s

6 0
4 years ago
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