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alisha [4.7K]
3 years ago
8

M=3000km v=25m/s what’s the momentum

Physics
1 answer:
valina [46]3 years ago
8 0
<h3>Answer:</h3>

Momentum of the given body will be : 75000 Kg m/s

<h3>Explanation:</h3>

According to Newton's first law of motion, all bodies continue to be in the state of rest or motion unless an external force is applied on the body. We can use this in the case of momentum also

The formula of momentum is given by :

:\implies \sf\quad \sf \:  P = mv

Here, we are given the mass of the body ( m ) as 3000kg and the velocity of the body ( v ) as 25 m/s. On putting the values in the formula:

\begin{aligned}&:\implies \sf\quad \sf \:  P = mv \\& :\implies \sf\quad \sf \:  P = 3000 \times 25 \\ & :\implies \sf\quad \sf \:   \boxed{ \sf \: P = 75000kgm {s}^{ - 1} } \end{aligned}

Momentum is associated with the mass of the moving body and can be defined as the quantity of motion measured as a product of mass and velocity.

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in an automobile crash, a vehicle was stopped at a red light is rear-ended by another vehicle. The vehicles have the same mass.
Masja [62]

8 m/s

Explanation:

Using conservation of momentum :-

m1u1 + m2v1 = m1u2 + m2v2

Where:

m1 = Mass of first vehicle

m2 = Mass of second vehicle

u1 = initial speed of first vehicle

v1 = initial speed of second vehicle

u2 = Final speed of first vehicle

v1 = Final speed of second vehicle

From the received informations:

m1 = m2

v1 = 0

v2 = u2 = 4 \frac{m}{s}

So

m1u1 + 0 = 4m1 + 4m1

Now divide both sides by m1 :-

u1 = 4 + 4

u1 = 8m/s

Therefore, final answer is 8 m/s

4 0
3 years ago
What is the mass of a sample whose specific heat is 6.28 J/g·°C if the sample absorbs 19.4 J and has a temperature increase of 2
kolbaska11 [484]
We have: Q = m.s.Δt
m = Q / s.Δt
Here, Q = 19.4 J
s = 6.28 J/g C
Δt = 22.9

Substitute their values into the expression:
m = 19.4 / 6.28×22.9
m = 19.4 / 143.81
m = 0.135 g

In short, Your Answer would be Option A

Hope this helps!
8 0
4 years ago
How long would it take a person to come to a stop if they were going
hammer [34]
33 mins hope it’s right
8 0
4 years ago
What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

#SPJ4

6 0
2 years ago
how many miles can you get on one tank of gas if your tank holds 18 gallons and you get 23 miles per gallon?
andrezito [222]
(18 gallon/tank) x (23 mile/gallon)  = <em>414 mile/tank</em> 
6 0
3 years ago
Read 2 more answers
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