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Nataly_w [17]
2 years ago
11

Define Nuclear Fission with an example of it​

Chemistry
2 answers:
ohaa [14]2 years ago
8 0

Answer:

Fission is the splitting of an atomic nucleus into two or more lighter nuclei accompanied by energy release. ... The energy released by nuclear fission is considerable. For example, the fission of one kilogram of uranium releases as much energy as burning around four billion kilograms of coal

Explanation:

Arlecino [84]2 years ago
6 0

Answer:

Fission is the splitting of an atomic nucleus into two or more lighter nuclei accompanied by energy release. The energy released by nuclear fission is considerable. For example, the fission of one kilogram of uranium releases as much energy as burning around four billion kilograms of coal.

PLEASE GIVE BRAINLIEST

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Cells which form pathways to and from the brain are <br> .epiltheilal neurons connnective
nikdorinn [45]

Answer:

<u><em>neurons</em></u>

Explanation:

The long-axoned cells, called principal neurons, transmit information over long distances from one brain region to another (Sheperd,1979). Principal neurons provide the pathways of communication within the nervous system.

3 0
2 years ago
Read 2 more answers
Balance the equation, Al203 + H2S04 to Al2(S04)3 + H20
lubasha [3.4K]

It is 1-3-1-3

so 1Al2O3 + 3H2So4 ---> 1Al2(So4)3 +  3H2O

8 0
3 years ago
If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
2 years ago
The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic attraction holding that compound
Nadya [2.5K]

Answer:

order = SrS > SrCl2 > RbCl > CsBr

Explanation:

Comparison of the melting points of compounds is basically dependent on the charge on their cation and anion, the more the charges on the cation and anion, the stronger and greater the force of attraction and as such the melting point will be relatively higher as well.

The ionic radii is also another factor to be considered, the more the distance between ions, the lesser the bond strength and the lesser the melting point.

from the options, in terms of ionic radii SrS > SrCl2 and RbCl > CsBr

also both SrS and SrCl2 have more charges on their ions compared to RbCl and CsBr and as such the arrangement of the highest melting point will be in the order SrS > SrCl2 > RbCl > CsBr.

6 0
3 years ago
QUESTION 17
borishaifa [10]

Question 17:

False; cutting hair would change what it looks like but, braiding it keeps it the same substance it is.


Question 18 :

My best guess would either be A or D. I would lean more towards D because if there are different mixtures then it depends on what you are mixing.


Hope it helps in some way. <3

5 0
2 years ago
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