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Alona [7]
4 years ago
15

Identify the component required for the electrolysis of molten nacl

Chemistry
1 answer:
EleoNora [17]4 years ago
4 0
The components required for the electrolysis of molten NaCl are a source of electrical energy such as a battery and electrodes (anode and cathode). Electrolysis is the process of decomposing and electrolyte (either and aqueous solution or molten solution) by passing an electric current through it. During electrolysis the positive ion moves to the negatively charged electrode (cathode), while the negatively charged ions go to the anode.
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Please help find Empirical formula! :)
mamaluj [8]

Answer:

The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound. It can be the same as the compound's molecular formula, but not always. An empirical formula can be calculated from information about the mass of each element in a compound or from the percentage composition

Explanatio internet bud

8 0
3 years ago
Is camphor heated a physical/chemical change​
DedPeter [7]

Answer:

when it is heated it changes to vapor, which is a physical change

Explanation:

7 0
4 years ago
What is the net ionic equation of the reaction below?
faltersainse [42]

Answer:

Net ionic equation:

 Ca⁺²(aq)  + CO²⁻₃(aq)     →   CaCO₃(s)

Explanation:

Chemical equation:

K₂CO₃  +   CaCl₂    →   KCl  +  CaCO₃

Balance chemical equation:

K₂CO₃(aq)  +   CaCl₂(aq)    →   2KCl(aq)  +  CaCO₃(s)

Ionic equation:

2K⁺(aq) + CO²⁻₃(aq)  +   Ca⁺²(aq)  + 2Cl⁻(aq)  →   2K⁺(aq) + 2Cl⁻(aq)  + CaCO₃(s)

Net ionic equation:

CO²⁻₃(aq)  +   Ca⁺²(aq)      →   CaCO₃(s)

The K⁺(aq) and Cl⁻ (aq) are spectator ions that's why these are not written in net ionic equation. The CaCO₃ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equatio n.

6 0
3 years ago
How many grams are there in 5 mol H20<br>Vour ans<br>BASE​
xxTIMURxx [149]

Answer:

\large \boxed{\text{90 g}}

Explanation:

\text{M$_{r}$ of H$_{2}$O} = 18.02\\\text{Mass} = \text{5 mol} \times \dfrac{\text{18.02 g}}{\text{1 mol}} = \text{90 g}\\\\\rm \text{There are $\large \boxed{\textbf{90 g}}$ in 5 mol of water.}

3 0
4 years ago
Study the figures below which illustrate the steps in the following chemical reaction:
Tanya [424]

Answer:

Hello - this is Mrs. Gussman, your chemistry teacher.  I wrote this exam question and posting it online is a violation of the academic integrity policy.  Remove this post immediately.

Explanation:

7 0
2 years ago
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