I think it's
<h2>
<em>C. Temperature is constant.</em></h2>
<em>Correct</em><em> </em><em>me</em><em> </em><em>if</em><em> </em><em>I'm</em><em> </em><em>wrong</em><em> </em>
<em>I</em><em> </em><em>hope it</em><em> </em><em>help</em><em> </em>
<em>#Carry</em><em> </em><em>on learning</em><em> </em>
<span>The turbine, since it is a rotary engine that turns into mechanical energy the energy of a stream of water, steam or gas. The basic element of the turbine is the wheel or rotor, which has blades, propellers, blades or hubs placed around its circumference, such that the moving fluid produces a tangential force that drives the wheel and turns it. This mechanical energy is transferred through an axis to provide movement of a machine, a compressor, an electric generator or a propeller.</span>
Answer:
see that the correct one is D
Explanation:
In this problem the satellite is subjected to the universal force of attraction
F = G M m / r²
using Newton's second law with centripetal acceleration you can find the angular velocity of the satellite
F = m a
F = m w² r
G M / r³ = w²
and w = 2π / T
In this case, the satellite is in a two-dimensional movement, where the free fall of the satellite is compensated by the horizontal displacement, for which it is always at a distance from the earth, remaining at the same point.
When reviewing the different statements we see that the correct one isD
Answer:
When it comes to serving, the court is divided into six zones. Right back is zone one, right front is zone two, middle front is zone three, left front is zone four, left back is zone five and middle back is zone six.
Explanation:
(a) The ball's height <em>y</em> at time <em>t</em> is given by
<em>y</em> = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²
where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve <em>y</em> = 0 for <em>t</em> :
0 = (20 m/s) sin(40º) <em>t</em> - 1/2 <em>g t</em> ²
0 = <em>t</em> ((20 m/s) sin(40º) - 1/2 <em>g t</em> )
<em>t</em> = 0 or (20 m/s) sin(40º) - 1/2 <em>g t</em> = 0
The first time refers to where the ball is initially launched, so we omit that solution.
(20 m/s) sin(40º) = 1/2 <em>g t</em>
<em>t</em> = (40 m/s) sin(40º) / <em>g</em>
<em>t</em> ≈ 2.6 s
(b) At its maximum height, the ball has zero vertical velocity. In the vertical direction, the ball is in free fall and only subject to the downward acceleration <em>g</em>. So
0² - ((20 m/s) sin(40º))² = 2 (-<em>g</em>) <em>y</em>
where <em>y</em> in this equation refers to the maximum height of the ball. Solve for <em>y</em> :
<em>y</em> = ((20 m/s) sin(40º))² / (2<em>g</em>)
<em>y</em> ≈ 8.4 m