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Naddik [55]
3 years ago
15

Suppose that a freely falling object were somehow equipped with an odometer. Would the readings of distance fallen each second i

ndicate equal or different falling distances for successive seconds? 1. Greater distances fallen in successive seconds 2. All are wrong. 3. Smaller distances fallen in successive seconds 4. Equal distances fallen in successive seconds 5. Initially equal distances fallen in successive seconds, then greater distances fallen in successive seconds
Physics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

1  greater distances fallen in successive seconds

Explanation:

When a body falls freely it is subjected to the action of the force of gravity, which gives an acceleration of 9.8 m / s2, consequently, we are in an accelerated movement

If we use the kinematic formula we can find the position of the body

       Y = Vo t + ½ to t2

Where the initial velocity is zero or constant and the acceleration is the acceleration of gravity

Y = - ½ g t2 = - ½ 9.8 t2 = -4.9 t2

Let's look for the position for successive times

t (s)      Y (m)

  1          -4.9

  2         -19.6

   3        -43.2

The sign indicates that the positive sense is up

It can be clearly seen that the distance is greatly increased every second that passes

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A 193nm-wavelength UV laser for eye surgery emits a 0.500mJ pulse. (a) How many photons does the light pulse contain?
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Two protons are 9.261 fm apart. (1 fm= 1 femtometer = 1 x 10^-15 m.) What is the ratio of the electric force to the gravitationa
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Answer:

1.24\times 10^{36}

Explanation:

q = magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C

m = mass of each proton = 1.67 x 10⁻²⁷ kg

r = distance between the two protons = 1 x 10⁻¹⁵ m

Electric force between the two protons is given as

F_{e} = \frac{kq^{2}}{r^{2}}

F_{e} = \frac{(9\times 10^{9})(1.6\times 10^{-19})^{2}}{(1\times 10^{-15})^{2}}

F_{e} = 230.4 N

Gravitational force between the two protons is given as

F_{g} = \frac{Gm^{2}}{r^{2}}

F_{g} = \frac{(6.67\times 10^{-11})(1.67\times 10^{-27})^{2}}{(1\times 10^{-15})^{2}}

F_{g} = 1.86\times 10^{-34} N

Ratio is given as

Ratio =\frac{F_{e}}{F_{g}}

Ratio =\frac{230.4}{1.86\times 10^{-34}}

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3 0
3 years ago
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Which of the following is a scalar quantity?
makvit [3.9K]

The only scalar quantity is a. 35 m

Explanation:

In physics, there are two types of quantities:

- Scalar: a scalar quantiy is a quantity having only a magnitude, so it is just a number followed by a unit. Examples of scalar quantities in physics are:

Speed

Energy

Distance

Time

- Vector: a vector quantity is quantity having both a magnitude and a direction. Examples of vector quantities in physics are:

Velocity

Force

Acceleration

Displacement

Let's now analyze each given option, to evaluate if it is a scalar or a vector:

a. 35m  --> it is only a unit (no direction), so it is a scalar

b. 20 m to the right  --> it has a direction, so it is a vector

c. 30 m to the North --> it has a direction, so it is a vector

So, the only correct option is a).

Learn more about scalars and vectors:

brainly.com/question/2678571

brainly.com/question/4945130

#LearnwithBrainly

4 0
3 years ago
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Answer:

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Solution:

As per the question:

The near point is 50.0 cm

Distance of the glasses from the eyeball, d = 2.00 cm

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Now,

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The object distance, u' = 25.0 - 2.00 = 23.0 cm

Now, using the Lens maker formula to calculate the focal length:

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\frac{1}{f} = \frac{1}{48.0} + \frac{1}{23.0} = 0.0643

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Now, the power of the lens in diopters is given by:

P = \frac{1}{f} = \frac{1}{15.549} = 0.0643 D

7 0
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