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Naddik [55]
4 years ago
15

Suppose that a freely falling object were somehow equipped with an odometer. Would the readings of distance fallen each second i

ndicate equal or different falling distances for successive seconds? 1. Greater distances fallen in successive seconds 2. All are wrong. 3. Smaller distances fallen in successive seconds 4. Equal distances fallen in successive seconds 5. Initially equal distances fallen in successive seconds, then greater distances fallen in successive seconds
Physics
1 answer:
maks197457 [2]4 years ago
3 0

Answer:

1  greater distances fallen in successive seconds

Explanation:

When a body falls freely it is subjected to the action of the force of gravity, which gives an acceleration of 9.8 m / s2, consequently, we are in an accelerated movement

If we use the kinematic formula we can find the position of the body

       Y = Vo t + ½ to t2

Where the initial velocity is zero or constant and the acceleration is the acceleration of gravity

Y = - ½ g t2 = - ½ 9.8 t2 = -4.9 t2

Let's look for the position for successive times

t (s)      Y (m)

  1          -4.9

  2         -19.6

   3        -43.2

The sign indicates that the positive sense is up

It can be clearly seen that the distance is greatly increased every second that passes

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A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the lef
stira [4]

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

4 0
3 years ago
A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

mg sin \theta - \mu N = ma (1)

where

mg sin \theta is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, \theta=39^{\circ} being the angle of the incline

\mu N is the frictional force, with \mu = 0.6 being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

N-mg cos \theta =0

where mg cos \theta is the component of the weight in the direction perpendicular to the slope. Solving for N,

N=mg cos \theta

Substituting into (1), solving for a, we find the acceleration:

a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2

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                             =  20 beetles / 5m²  =  4 beetles per m²
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Match the terms in Column II with the descriptions in Column I. Write the letters of the correct term in the blank on the left.
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What characteristics are shared by both heating and cooling curves? choose 4
Luda [366]

The characteristics shared by both heating and cooling curves is that phases changes when the temperature stays the same.

<h3>What is heating and cooling?</h3>

Heating is the process by which the temperature of a place or substances or object is increased.

Cooling Is the process of lowering the temperature of a substance or object by using conditioners or by freezing .

Therefore, The characteristics shared by both heating and cooling curves is that phases changes when the temperature stays the same.

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