Answer:
m/s
Explanation:
Position/Displacement is measured in meters (m).
Velocity is measured in meters per second (m/s).
Acceleration is measured in meters per second squared (m/s²).
Answer:![\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Chat%7Bi%7D%5B-329.11%5D%2B%5Chat%7Bj%7D%5B516.18%5D)
Explanation:
Given
Plane is initially flying with velocity of magnitude ![v=600\ mph](https://tex.z-dn.net/?f=v%3D600%5C%20mph)
at angle of
with North towards west
Velocity of plane airplane can be written as
![v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})](https://tex.z-dn.net/?f=v_a%3D600%28-%5Csin%2040%5Chat%7Bi%7D%2B%5Ccos%2040%5Chat%7Bj%7D%29)
Now wind is encountered with speed of
at angle of ![N45^{\circ}E](https://tex.z-dn.net/?f=N45%5E%7B%5Ccirc%7DE)
![v_w=80(\cos 45\hat{i}+\sin 45\hat{j})](https://tex.z-dn.net/?f=v_w%3D80%28%5Ccos%2045%5Chat%7Bi%7D%2B%5Csin%2045%5Chat%7Bj%7D%29)
resultant velocity
![\vec{v_R}=\vec{v_a} +\vec{v_w}](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Cvec%7Bv_a%7D%20%2B%5Cvec%7Bv_w%7D)
![\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D600%28-%5Csin%2040%5Chat%7Bi%7D%2B%5Ccos%2040%5Chat%7Bj%7D%29%2B%2080%28%5Ccos%2045%5Chat%7Bi%7D%2B%5Csin%2045%5Chat%7Bj%7D%29)
![\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Chat%7Bi%7D%5B-385.67%2B56.56%5D%2B%5Chat%7Bj%7D%5B459.62%2B56.56%5D)
![\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]](https://tex.z-dn.net/?f=%5Cvec%7Bv_R%7D%3D%5Chat%7Bi%7D%5B-329.11%5D%2B%5Chat%7Bj%7D%5B516.18%5D)
for direction ![\tan \theta =\frac{516.18}{329.11}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%5Cfrac%7B516.18%7D%7B329.11%7D)
![\tan \theta =1.568](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D1.568)
west of North
Explanation:
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