CThe answer is 64%.
(1) Calculate the molar mass of N2O which is the sume of atomic masses of its elements:
Mr(N2O) = 2Ar(N) + Ar(O)
Ar(N) = 14 g
Ar(O) = 16 g
Mr(N2O) = 2 * 14 + 16 = 28 + 16 = 42 g
(2) Calculate mass percentage of nitrogen in N2O.
Total mass is 44 g: 44g is 100%
Mass of nitrogen is 28 g: 28g is x%
44 g : 100% = 28 g : x
x = 28 g * 100% : 44 g
x = 63.64% ≈ 64%
Oxygen is a liquid under one atmosphere. the boiling point of a substance is the temperature at which vapor pressure of a liquid is equal to the pressure of the surrounding liquid. the boiling point of oxygen at this case is 90.0k. Therefore the temperature of oxygen is 90-273= -183 celsius scale
Well, I say the answer is Thermosphere! Hope I helped :)
Answer:
See detailed explanation.
Explanation:
Hello!
In this case, for the reaction:
It is known that the equilibrium constant tends to be greater than 1; therefore, it is a reaction that tends to go rightwards towards the formation of hydrogen iodide.
a) Here, since the reaction tends to form the product, it is clear that the initial concentration of iodine and hydrogen will decrease as the reaction reaches equilibrium in order to increase the concentration of hydrogen iodide.
b) Yes, it stops at the point in which the following expression:
Equals the equilibrium constant.
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Answer:
C2H4Cl
Explanation:
The first step in obtaining the empirical formula is to divide the percent by mass of each element by its relative atomic mass;
C- 37.83/12, H- 6.35/1, Cl- 55.83/35.5
3.15, 6.35, 1.57
Divide through by the lowest ratio
3.15/1.57, 6.35/1.57, 1.57/1.57
2, 4, 1
Hence, empirical formula is C2H4Cl