Answer:
The total energy to break all the bonds in 1 mole of 1-propanol, C₃H₈O, is 4411 kJ/mol
Explanation:
We note that propanol, C₃H₈O is also known as 1-propanol is written as follows;
CH₃CH₂CH₂OH which gives
CH₃-CH₂-CH₂-OH
Hence, the total number of bonds are;
C-H Bonds = 3 + 2 + 2 = 7
C-O Bonds = 1
O-H Bond = 1
C-C Bonds = 2
The bond energies are as follows;
C-H Bonds = 413 kJ/mol
C-O Bonds = 358 kJ/mol
O-H Bond = 468 kJ/mol
C-C Bonds = 347 kJ/mol
Energy required to break the bonds in 1-propanol is therefore;
C-H Bonds = 413 kJ/mol × 7 = 2,891 kJ/mol
C-O Bonds = 358 kJ/mol × 1 = 358 kJ/mol
O-H Bond = 468 kJ/mol × 1 = 468 kJ/mol
C-C Bonds = 347 kJ/mol × 2 = 694 kJ/mol
The total energy to break all the bonds in 1 mole of 1-propanol = 4411 kJ/mol.
I am not for sure, but i think it explodes :)
The numerical value of Kc is 1.129 x10^4
<u><em> Explanation</em></u>
C3H6O +4O2→ 3 CO2 + 3H2O
KC is the ratio of concentration of the product over the reactant.
Each concentration of product and reactant are raised to the power of its coefficient.
Therefore the KC expression of equation above is
Kc=[ (Co2)^3 (H2O)^3] / [(C3H6O) (O2)^4)]
Kc =[(1.8^3) x (2.0^3)] / [(0.51) x (0.30^4)] =1.129 x10^4
Answer:
The correct answer is C ions from the solute molecules have a strong attraction to the polar solvent molecules.
Explanation:
NaCl or Sodium chloride is an ionic compound which easily get dissolved in polar molecular compound such as water(H2O).
Both NaCl and H2O are polar compound because the atoms that forms NaCl and H2O have vast difference in their electronegativities.As a result the bonding electrons in both NaCl and H2O are not equally shared.
NaCl get dissolved in water molecules by dipole dipole interaction.
