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4 years ago

The area of a triangle with a base of 4 meters and a height of 6 meters.

Chemistry

2 answers:

Tanya [424]4 years ago

8 0

Answer: I believe the answer is 12

Explanation:

Gemiola [76]4 years ago

4 0

Area of triangle = 1/2(b)(h)

So, area = (1/2 × 4 × 6)m^2

= (2 × 6)m^2

= 12 m^2

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1) If you have 2.6 moles of iron (III) oxide, how many molecules of iron (III)

Ugo [173]

Answer:

234

Explanation:

so 3 x 3 x 26 =234

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3 years ago

In a chemical reaction, the products are

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4 years ago

Read 2 more answers

An empty beaker weighs 25.91 g. When completely filled with water, the beaker and its contents have a total mass of 333.85 g. Wh

Finger [1]

Answer:

The beaker holds 307.94 mL

Explanation:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

weight of water (m) = total weight - weight of beaker

Empty weight of beaker = 25.91 g

Weight of beaker with water = 333.85 g

Weight of water = 333.85 - 25.91 = 307.94 g

Density of water = 1 g/mL

We have

Mass = Volume x density

307.94 = Volume x 1

Volume = 307.94 mL

The beaker holds 307.94 mL

3 0

3 years ago

Which best describes the pH scale?

oksano4ka [1.4K]

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3 years ago

A hydrocarbon is burnt completely to give 3.447g of

goblinko [34]

Answer: The empirical formula for the given compound is $CH_2$

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, iron and oxygen follows:

$C_xH_y+O_2\rightarrow CO_2+H_2O$

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of $CO_2=3.447g$

Mass of $H_2O=1.647g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 3.447 g of carbon dioxide, $\frac{12}{44}\times 3.447=0.940g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.647 g of water, $\frac{2}{18}\times 1.647=0.183g$ of hydrogen will be contained.

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.940g}{12g/mole}=0.0783moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.183g}{1g/mole}=0.183moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0783 moles.

For Carbon = $\frac{0.0783}{0.0783}=1$

For Hydrogen = $\frac{0.183}{0.0783}=2.34\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H = 1 : 2

Hence, the empirical formula for the given compound is $CH_2$

8 0

3 years ago