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timama [110]
3 years ago
13

The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti

mate the approximate Zeff felt by a valence electron of boron and oxygen, respectively?
Chemistry
1 answer:
nadezda [96]3 years ago
3 0

<span>
</span>The solution would be like this for this specific problem:

<span> (atomic number) - (core electrons)</span> 

Boron:

Atomic number: 5 
Core electrons: 2

Boron will have the following: 2 core electrons and 3 valence electrons.
(atomic number) - (core electrons)------> (5) - (2) = +3 

<span>
</span><span>Oxygen: </span><span>
<span>Atomic number: 8 </span>
<span>Core electrons: 2 </span></span>

<span>Boron will have the following: 2 core electrons and 6 valence electrons. </span><span>
<span>(atomic number) - (core electrons)------> (8) - (2) = +6 |

So the answer would be +3 and +6</span>.</span><span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
An amphoteric salt is one that contains an anion that can act as either an acid or a base in water. Baking soda, NaHCO3, is an e
LenKa [72]

Answer:

pH = 8.34

Explanation:

The equilbriums of the amphoteric HCO₃⁻ (Ion of NaHCO₃) are:

H₂CO₃ ⇄ <em>HCO₃⁻</em> + H⁺ Ka1 <em>-Here, HCO₃⁻ is acting as a base-</em>

<em>HCO₃⁻</em>⇄ CO₃²⁻ + H⁺ Ka2 <em>-Here, is acting as an acid-</em>

Where Ka1 = 4.3x10⁻⁷ and Ka2 = 4.8x10⁻¹¹. As pKa = -log Ka:

pKa1 = 6.37; pKa2 = 10.32

As the pH of amphoteric salts is:

pH = (pKa1 + pKa2) / 2

<h2>pH = 8.34</h2>
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2 years ago
In science what can only be separated by Chemical methods​
PilotLPTM [1.2K]

Answer:

A mixture is a physical combination of substances thus it only requires physical processes to separate.

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A compound is determined to have the empirical formula C2OH4. If the molar mass of the compound is 132 g/mol, determine the mole
8_murik_8 [283]

Answer: The molecular formula will be C_6O_3H_{12}

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

Empirical weight of C_2OH_{4} is 12\times 2+16\times 1+1\times 4=44g

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Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight}}{\text{Equivalent weight}}=\frac{132}{44}=3

The molecular formula will be=3\times C_2OH_4=C_6O_3H_{12}

5 0
3 years ago
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