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timama [110]
3 years ago
13

The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti

mate the approximate Zeff felt by a valence electron of boron and oxygen, respectively?
Chemistry
1 answer:
nadezda [96]3 years ago
3 0

<span>
</span>The solution would be like this for this specific problem:

<span> (atomic number) - (core electrons)</span> 

Boron:

Atomic number: 5 
Core electrons: 2

Boron will have the following: 2 core electrons and 3 valence electrons.
(atomic number) - (core electrons)------> (5) - (2) = +3 

<span>
</span><span>Oxygen: </span><span>
<span>Atomic number: 8 </span>
<span>Core electrons: 2 </span></span>

<span>Boron will have the following: 2 core electrons and 6 valence electrons. </span><span>
<span>(atomic number) - (core electrons)------> (8) - (2) = +6 |

So the answer would be +3 and +6</span>.</span><span>

I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

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Answer:

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3 years ago
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6 0
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4 0
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A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
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[HA] is the concentration of the acid

Given:
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