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Alex Ar [27]
3 years ago
5

Ghhhhh ?byhjejjssj jajjsjjs jksjss jisjjsjzh jsjjsjs

Chemistry
2 answers:
defon3 years ago
5 0

Answer:

What type of question is this?

Explanation:

USPshnik [31]3 years ago
5 0

I understand what I must do,

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What is a mutation?
Masja [62]

Answer:

the answer is A hope this helps

3 0
3 years ago
A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
How many molecules are in 10.0 miles of C2H6O
shutvik [7]
6.02 x 10²⁴ molecules of C2H6O
3 0
3 years ago
50 POINTS*** Which of the following is not a correct chemical equation for a double displacement reaction?
hammer [34]
I mostly believe in between D and B beacuse K3po4 and caco3 is not an element equation

4 0
3 years ago
Read 2 more answers
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
3 years ago
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