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Alex Ar [27]
4 years ago
5

Ghhhhh ?byhjejjssj jajjsjjs jksjss jisjjsjzh jsjjsjs

Chemistry
2 answers:
defon4 years ago
5 0

Answer:

What type of question is this?

Explanation:

USPshnik [31]4 years ago
5 0

I understand what I must do,

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650.J is the same amount of energy as? <br>2720cal<br>1550cal<br>650.cal<br>2.72cal
Oksi-84 [34.3K]

<u>Ans: 650 J = 155 calories</u>


<u>Given:</u>

Energy in joules = 650 J

<u>To determine:</u>

The energy in calories

<u>Explanation:</u>

1 joule = 0.2388 calories

Therefore, 650 joules = 0.2388 calories * 650 J/1 J = 155 calories

4 0
4 years ago
Read 2 more answers
How many electrons in an atom can have a quantum number of n = 2?
yuradex [85]
It would be 18 electrons i think 
4 0
3 years ago
Hydrochloric acid reacts with sodium hydroxide to produce sodium chloride and water. If 20.6 g of sodium hydroxide reacts with a
astraxan [27]

Answer:

30.1 g NaCl

Explanation:

Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.

20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl

4 0
3 years ago
4) Type only the NUMBER answer to the question below (no units). Your
Nataliya [291]
(4.5 x 10^24 molecules) x (60.013 g / 6.022 x 10^23) = 448 grams or 4.484 x 10^2 grams = Answer
3 0
2 years ago
A solution of is found to have 37% transmittance at 447 nm. If the molar absorption coefficient (ε) is 4400 at 477 nm, what is t
inn [45]

Answer:

The concentration of the solution is 1.068×10⁻⁴M

Explanation:

Hello,

To find the concentration of the solution, we'll have to use Beer-Lambert law which states absorption is directly proportional to the concentration of the solution.

Beer-Lambert law = A = εCL

A = absorption = 2 - log₁₀%T = 2 - log₁₀(34)

A = 2 - 1.5314 = 0.47

A = 0.47

ε = molar absorption coefficient = 4400

C = concentration of the solution

L = path length = 1cm

A = εcl

C = A / εl

C = 0.47 / 4400 × 1

C = 1.068×10⁻⁴M

The concentration of the solution is 1.068×10⁻⁴M

3 0
4 years ago
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