Answer:
the answer is A hope this helps
Answer:
The answer to your question is the mass of solute = 53.5 g
Explanation:
Data
mass of solution = 482 g
mass of solute = ?
mass percent = 11.1 %
Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution
Process
1.- Write the formula
Mass percent = mass of solute / mass of solution x 100
-Solve for mass of solute
mass of solute = Mass percent x mass of solution / 100
2.- Substitution
mass of solute = 11.1 x 482 / 100
3.- Simplification
mass of solute = 5350.2 / 100
4.- Result
mass of solute = 53.5g
6.02 x 10²⁴ molecules of C2H6O
I mostly believe in between D and B beacuse K3po4 and caco3 is not an element equation
The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:

Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336