State where the chemical potential energy released from a reaction is stored

Balance the following chemical equation: <br> ___HCO + ___O —> ___H2 + ___CO3

yawa3891 [41]

Answer: 2HCO + 4O → H2 + 2CO3

Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide

Reaction Type: SINGLE REPLACEMENT

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7 0

3 years ago

for: rate=k[A]^x determine the value of x if the rate doubles when [A] is doubled; and if the rate quadruples when [A] is double

Rom4ik [11]

<span>1. The value of x if the rate doubles when [A] is doubled is that </span><span>x = 1

</span><span>2. Then if the rate quadruples when [A] is doubled is that x= 2
Since x=1 when the rate doubles, so if it quadruples, it will be times 2.
So the solution to this is 1 times 2= 2
x=2</span>

5 0

4 years ago

Read 2 more answers

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

GREYUIT [131]

The element that was oxidized is carbon, as it’s oxidation state increased (electrons were lost) from +2 (in the reactants) to +4 (in the products). The element that was reduced is nitrogen, as it gained electrons and went from a +2 oxidation state (reactants) to a 0 oxidation state (products). Since the carbon was oxidized and it’s electrons were used to reduce the nitrogen, carbon is the reducing agent.

7 0

4 years ago

A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X

Tasya [4]

$\LARGE{ \boxed{ \rm{ \red{Required \: answer}}}}$

☃️ Chemical formulae ➝ $\sf{CaCO_3}$

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{No. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}$

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of $\sf{CaCO_3}$

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0

4 years ago

Read 2 more answers

What is the molarity of a sodium carbonate solution containing 32.52 g Na2CO3 dissolved in enough water to make 822 ml of soluti

svet-max [94.6K]

The molarity of a Sodium carbonate solution : 0.373 M

<h3>Further explanation</h3>

Given

32.52 g Na₂CO₃

822 ml of solution = 0.822 L

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

mol of solute = mol of Na₂CO₃ :

= mass : MW Na₂CO₃

= 32.52 g : 106 g/mol

= 0.307

Molarity :

= n : V

= 0.307 mol : 0.822 L

= 0.373 M

8 0

3 years ago