Emission spectrum, mass spectrum does not make sense and neither does atoms spectrum. You use the emission spectrum to compared known elements in a star to the unknown elements in a star. Hope this help!
The answers go as following: H, C, D, F, J, G, B, A, E, I.
I’m sure you’re smart, don’t get yourself down. Just apply yourself and focus.
Answer:
What you need to know before I explain is how to add percents onto numbers. What I'm saying is what and how to do 6.4% x 1500
1. You can't do a percent and number together, that's impossible
What you can do is convert the percent (6.4%) into a decimal
2. 6.4% is equivalent to 6.4/100, which is equivalent to 0.064
3. Now, you multiply 0.064 x 1500
You will notice, hopefully, that you have a number smaller than 1500, but do not panic, you are on the right track!
4. Using the number you got, add that to 1500, and there's your total!
But, if you want only the tax, keep that small number you started off with!
Explanation:
Answer:
3) The relative concentrations of each gas must remain constant.
4)The concentration of each gas will not change.
Explanation:
- For the equilibrium system:
<em>X₂ + Y₂ ⇄ 2XY,</em>
The no. of moles of gases in each side is constant; there is 2 moles of gases at reactants side and 2 moles of gases at products side.
So, changing the volume will not affect on the equilibrium system.
<em>So, the right choice is:</em>
3) The relative concentrations of each gas must remain constant.
4)The concentration of each gas will not change.
Answer:
Kₐ = 5.7 x 10⁻⁵
Explanation:
The equilbrium for this acid is
HC₃H₃CO₂ + H2O ⇄ H₃O⁺ + C₃H₃CO₂ ⁻ ,
and the equilibrium constant for acrylic acid is given by the expression:
Kₐ = [ H₃O⁺][ C₃H₃CO₂⁻ ] / [ HC₃H₃CO₂ ]
Since the pH of the 0.23 M solution is known , we can calculate [ H₃O⁺].
The ][ C₃H₃CO₂⁻ ] is equal to [ H₃O⁺] from the above equilibria (1:1)
Finally [ HC₃H₃CO₂ ] is known.
pH = - log [ H₃O⁺]
taking antilog to both sides of the equation
10^-pH = [ H₃O⁺]
Substituting
10^-2.44 = [ H₃O⁺] = 3.6 x 10⁻³
[ C₃H₃CO₂⁻ ] = 3.6 x 10⁻³
Kₐ = ( 3.6 x 10⁻³ ) /0 .23 = 5.7 x 10⁻⁵
