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3 years ago

6

What is the reactivity trend of halogens?

1 answer:

RSB [31]3 years ago

3 0

Reactivity trends of halogen:

1) Melting point and boiling points increased down the
group

2) Colour becomes darker.
E.g. Fluorine (pale yellow)
Chlorine (yellowish-green)
Bromine (reddish-brown)
Iodine (purplish-black)
Astatine (black)

3) The reactivity decreases down the group.
Reactivity:
F > Cl > Br > I > At

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An unknown compound in the lab is either LiOH, CaF2, or LiF. If the sample has a mass of 260 grams and contains 3.33 moles, what

sergij07 [2.7K]

Answer:

CaF2

Explanation:

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3 years ago

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Explanation:

1mm = 1/10 cm

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3 years ago

When naming acids such as HCl, HBr, and HI, the prefix "hydro-" is added and the "ine" of the element is replaced with which of

liberstina [14]

Answer:

a. "-ic"

Explanation:

The correct answer is a. "-ic".

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For HCl, the name is Hydrochloric acid. As you can see, the suffix "-ine" of the element (originally chlor<em>ine</em>) is changed to "-ic".

Following the same logic, the name for HBr is Hydrobromic acid; and the name for HI is Hydroiodic acid.

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3 years ago

Enter your answer in the provided box. The usefulness of radiocarbon dating is limited to objects no older than 50,000 yr. What

guapka [62]

Answer : The percent of the carbon−14 left is, 0.242 %

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

To calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5.73\times 10^3\text{ years}}$

$k=1.205\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount left.

Expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = $1.205\times 10^{-4}\text{ years}^{-1}$

t = time taken for decay process = 50000 years

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Putting values in above equation, we get:

$1.205\times 10^{-4}=\frac{2.303}{50000\text{ years}}\log\frac{7g}{a-x}$

$a-x=0.0169g$

The amount left of carbon-14 = 0.0169 g

Now we have to calculate the percent of the carbon−14 left.

$\text{Percent of carbon}-14\text{ left}=\frac{\text{Amount left of carbon}-14}{\text{Original amount of carbon}-14}\times 100$

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3 years ago

Which is more polar: A. [ Select ] Br-Cl or F-Cl B. [ Select ] H-O or Se-H C. [ Select ] As-H or N-S

Marysya12 [62]

Answer:

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Explanation:

Polarity of a bond is determined by the Electronegativity across the period and its group.

So un the basis of that.

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2 years ago