Answer:
The volume of the gas will be 78.31 L at 1.7 °C.
Explanation:
We can find the temperature of the gas by the ideal gas law equation:
![PV = nRT](https://tex.z-dn.net/?f=%20PV%20%3D%20nRT%20)
Where:
n: is the number of moles
V: is the volume
T: is the temperature
R: is the gas constant = 0.082 L*atm/(K*mol)
From the initial we can find the number of moles:
![n = \frac{P_{1}V_{1}}{RT_{1}} = \frac{1 atm*62.65 L}{(0.082 L*atm/K*mol)*(0 + 273)K} = 2.80 moles](https://tex.z-dn.net/?f=%20n%20%3D%20%5Cfrac%7BP_%7B1%7DV_%7B1%7D%7D%7BRT_%7B1%7D%7D%20%3D%20%5Cfrac%7B1%20atm%2A62.65%20L%7D%7B%280.082%20L%2Aatm%2FK%2Amol%29%2A%280%20%2B%20273%29K%7D%20%3D%202.80%20moles%20)
Now, we can find the temperature with the final conditions:
![T_{2} = \frac{P_{2}V_{2}}{nR} = \frac{612.0 mmHg*\frac{1 atm}{760 mmHg}*78.31 L}{2.80 moles*0.082 L*atm/(K*mol)} = 274.7 K](https://tex.z-dn.net/?f=%20T_%7B2%7D%20%3D%20%5Cfrac%7BP_%7B2%7DV_%7B2%7D%7D%7BnR%7D%20%3D%20%5Cfrac%7B612.0%20mmHg%2A%5Cfrac%7B1%20atm%7D%7B760%20mmHg%7D%2A78.31%20L%7D%7B2.80%20moles%2A0.082%20L%2Aatm%2F%28K%2Amol%29%7D%20%3D%20274.7%20K%20)
The temperature in Celsius is:
![T_{2} = 274.7 - 273 = 1.7 ^{\circ} C](https://tex.z-dn.net/?f=%20T_%7B2%7D%20%3D%20274.7%20-%20273%20%3D%201.7%20%5E%7B%5Ccirc%7D%20C%20)
Therefore, the volume of the gas will be 78.31 L at 1.7 °C.
I hope it helps you!
Primary:
Grasshopper
Mouse
Grass
Secondary:
Hawk
Snake
Coyote
Answer:
Curvature
Explanation:
In mathematics, curvature is any of several strongly related concepts in geometry. Intuitively, the curvature is the amount by which a curve deviates from being a straight line, or a surface deviates from being a plane. For curves, the canonical example is that of a circle, which has a curvature ... For being meaningful, the definition of the curvature and its different
Answer:
1.03 M
Explanation:
Step 1: Write the balanced equation
NaOH + HCl ⇒ NaCl + H₂O
Step 2: Calculate the reacting moles of HCl
30.0 mL (0.0300 L) of 0.500 M HCl react.
0.0300 L × 0.500 mol/L = 0.0150 mol
Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl
The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.
Step 4: Calculate the molar concentration of NaOH
0.0150 moles of NaOH are in 14.5 mL (0.0145 L).
M = 0.0150 mol/0.0145 L = 1.03 M