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harina [27]
3 years ago
4

Arrange the following atoms in order of increasing atomic radius: potassium, carbon, rubidium, iodine, fluorine, and lithium. Ex

plain your order.
Chemistry
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

fluorine ∠ Carbon ∠ Iodine ∠ lithium ∠ Potassium ∠ Rubidium

Explanation:

Atomic radii values in Å

Potassium  2.43

Carbon  0.67

Rubidium  2.65

Iodine  1.15

fluorine  0.42

lithium  1.67

Atomic radii trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

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when heating copper in the final step, the bright copper color changes to a dull brown. will the percent recovery be too high or
jasenka [17]
<span>When heating copper in the final step, the bright copper color changes to a dull brown. I think this process will make the percent recovery low because a change in color can mean some reacted. Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
Is this experiment okay for this question???? If not, what would a good one be?
Fed [463]
Yes that would be ok, explain how it works though.
6 0
4 years ago
What current (in a) is required to plate out 2. 96 g of nickel from a solution of ni2 in 27. 12 minutes?
amid [387]

The current required to plate out 2.96 g of nickel from the solution of Ni²⁺ in 27.12 minutes is 5.95 A

<h3>Balanced equation </h3>

We'll begin by writing the balanced equation showing the number of faraday required to plate nickel. This is given below

Ni²⁺ + 2e —> Ni

Molar mass of Ni = 59 g/mol

Mass of Ni from the balanced equation = 1 × 59 = 59 g

Number of faraday = 2 F

1 faraday = 96500 C

2 faraday = 2 × 96500 = 193000 C

SUMMARY

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

<h3>How to determine the quantity of electricity </h3>

From the balanced equation above,

59 g of Nickel was deposited by 193000 C of electricity

Therefore,

2.96 g of Nickel will be deposited by = (2.96 × 193000) / 59 = 9682.71 C of electricity

<h3>How to determine the current </h3>
  • Quantity of electricity (Q) = 9682.71 C
  • Time (t) = 27.12 mins = 27.12 × 60 = 1627.2 s
  • Current (I) =?

I = Q / t

I = 9682.71 / 1627.2

I = 5.95 A

Learn more about Faraday's law:

brainly.com/question/24795850

6 0
2 years ago
Read 2 more answers
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
How does velocity and mass affect momentum?
ollegr [7]

Velocity and mass are directly proportional to the quantity of momentum by:

p = mv. Therefore, and increase in either velocity or mass will lead to an increase in momentum and vice versa. Momentum during a reaction is always conserved, meaning that the mass and initial velocity before a reaction will always be equal to the change in mass and velocity produced after the reaction. Kinetic energy after a reaction, however, is not always conserved. For example if a fast moving vehicle collided with a stationary vehicle, and moved together, the overall kinetic energy would be after the reaction, as a heaver mass would be moved by the same velocity causing a decrease in kinetic energy.

I don't know if this is exactly what you are looking for, but in physics this is how it is understood.

4 0
3 years ago
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