How many grams of strontium are in 2.92 moles of strontium

Chemistry

2 answers:

Allisa [31]3 years ago

8 0

The answer to this is 255.85 grams

Fiesta28 [93]3 years ago

7 0

Question: How many grams of Strontium are in 2.92 moles of Strontium

There are 0.011412919424789 moles in one gram of Strontium.

In 2.92 moles of Strontium there are 255.8504 grams of Strontium.

Strontium is an alkaline earth metal. It is a highly reactive chemical. And is usually silver-white yellowing in color. And can also treat Osteoporosis for bones.

Final Answer:

In 2.92 moles of Strontium there are 255.8504 grams of Strontium.

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Need help pleas can some body helpe me?

Pani-rosa [81]

Answer:

they are not liquids at room temperature, so your answer is the last one

Explanation:

5 0

3 years ago

Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi

marta [7]

Answer : The value of $K_{goal}$ for the final reaction is, $1.238\times 10^{-7}$

Explanation :

The following equilibrium reactions are :

(1) $2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2$ $K_1=5.40\times 10^{-16}$

(2) $2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l)$ $K_2=1.06\times 10^{10}$

(3) $CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g)$ $K_3=2.68\times 10^{-9}$

The final equilibrium reaction is :

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$ $K_{goal}=?$

Now we have to calculate the value of $K_{goal}$ for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

$K_{goal}=\sqrt{K_1\times K_2\times K_3}$