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Zolol [24]
2 years ago
5

What is the density of an aqueous solution that is 50.0% KOH by mass and has a KOH concentration of 13.39 M?

Chemistry
1 answer:
Contact [7]2 years ago
7 0

Answer:

Density = 1.56 g/mL

Explanation:

We have two sort of concentrations in here, so let's combine them.

% by mass means grams of solute in 100 g of solution

M means, moles of solute in 1L of solution.

We know that our solute is KOH (Molar mass = 56.1 g/mol)

We convert the moles of solute to grams:

56.1 g/mol . 13.9 moles = 779.79 g

Now, we know that 50 g of solute are in 100 g of solution

Then, 779.79 g of solute will be contained in (100 . 779.79)/50 = 1559.58 g of solution

Density = mass / volume

1559.58 g of solution / 1000 mL of solution = 1.56 g/mL

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The mass of a block is 12 grams and the volume is 6 ml. Calculate the density of the
KengaRu [80]

Answer:

The density of block is 2 g/mL.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass of block = 12 g

volume =  6 mL

density = ?

Now we will put the values in the formula,

d= m/v

d = 12 g/ 6 mL

d = 2 g/mL

so, the density of block is 2 g/mL .

3 0
2 years ago
48 points
ahrayia [7]

Answer:

1. Matter

2. Mass

3. Space/Volume

4. Substances

5. Atomic

6. Positively

7. Neutrally charged

8. Negatively

9. Atomic

10.  Nucleus

11.

12. Atomic

13. Ions

14. Cation

15. Anion

16. Isotopes

6 0
3 years ago
Chất nào sau đây là chất điện li mạnh trong H2O
erica [24]

Answer:

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Explanation:

Hy vọng nó sẽ giúp ích;>

3 0
3 years ago
Read 2 more answers
Will give brainlsit need answers asap!
k0ka [10]

Answer:

120 g of NaCl in 300 g H20   at 90 C

Explanation:

At x = 90   go vertical to the line for NaCl...then go left to the y-axis to find the solubility in 100 g H20   = 40

we want   300 g H20    so multiply this by  3    to get   120 gm of NaCl in 300 g

7 0
1 year ago
A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to
melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:

  • pH = pKa + log\frac{[CH_3COO^-]}{[CH_3COOH]}

For acetic acid, pKa = 4.75.

We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:

  • CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
  • CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:

  • pH = 4.75 + log\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L} = 5.54
6 0
3 years ago
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