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goldenfox [79]
3 years ago
6

(2 points) Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas

and an aqueous solution of magnesium (II) chloride. What substance is being oxidize
Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

<u>Answer:</u> In the given chemical equation, the substance getting oxidized is magnesium metal.

<u>Explanation:</u>

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

The chemical equation for the reaction of magnesium and hydrochloric acid follows:

Mg(s)+2HCl(aq.)\rightarrow MgCl_2(aq.)+H_2(g)

The half reaction for the above equation follows:

<u>Oxidation half reaction:</u> Mg(s)\rightarrow Mg^{+}(aq.)+2e^-

<u>Reduction half reaction:</u> 2H^+(aq.)\rightarrow H_2(g)+2e^-

Hence, in the given chemical equation, the substance getting oxidized is magnesium metal.

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C. Ninhydrin is used to detect prints on a non-porous surface
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3 years ago
Nitrosyl bromide decomposes according to the chemical equation below. 2NOBr(g) 2NO(g) + Br2(g) 1.00 atm of NOBr is sealed in a f
Andrew [12]

Given :

2NOBr(g) - -> 2NO(g) + Br2(g)

Initial pressure of NOBr , 1 atm .

At equilibrium, the partial pressure of NOBr is 0.82 atm.

To Find :

The equilibrium constant for the reaction .

Solution :

             2NOBr(g) - -> 2NO(g) + Br2(g)

t=0 s           1 atm                 0             0

t=t_{eqb}       1( 1-2x)               2x           x

So ,

1-2x=0.82\\\\x=0.09

At equilibrium :

K_{eq}=\dfrac{[NO]^2[br_2]}{[NOBr]^2}\\\\K_{eq}=\dfrac{0.18^2\times 0.9}{0.82^2}\\\\K_{eq}=0.043\ atm

Hence , this is the required solution .

3 0
3 years ago
Which rock would be the best source of the mineral garnet?
n200080 [17]
(4) slate because it is the strongest
5 0
3 years ago
Read 2 more answers
A sample of sugar (C12H22O11) contains
Lady_Fox [76]

4 moles of sugar.

Explanation:

A mole is defined as the amount of a substance contained in Avogadro's number of particles 6.02 x 10²³.

    1 mole of substance  = 6.02 x 10²³. molecules

Given that;

  the sample of sugar contains 1.505 x 10²³.molecules

  The number of moles in this amount of sugar is 4 moles

Learn more:

Number of moles brainly.com/question/13064292

#learnwithBrainly

5 0
3 years ago
Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0
3 years ago
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