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goldenfox [79]
3 years ago
6

(2 points) Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas

and an aqueous solution of magnesium (II) chloride. What substance is being oxidize
Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

<u>Answer:</u> In the given chemical equation, the substance getting oxidized is magnesium metal.

<u>Explanation:</u>

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

The chemical equation for the reaction of magnesium and hydrochloric acid follows:

Mg(s)+2HCl(aq.)\rightarrow MgCl_2(aq.)+H_2(g)

The half reaction for the above equation follows:

<u>Oxidation half reaction:</u> Mg(s)\rightarrow Mg^{+}(aq.)+2e^-

<u>Reduction half reaction:</u> 2H^+(aq.)\rightarrow H_2(g)+2e^-

Hence, in the given chemical equation, the substance getting oxidized is magnesium metal.

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Methanethiol, CH3SH, has a substantial dipole mement (1.52) even though carbon and sulfer have identical electronegativities. Ex
AleksAgata [21]

Answer:

The whole molecule is polar because Sulfur has lone pairs but Carbon doesn't. Lone pairs count more toward polarity, shifting dipole toward S.

Explanation:

Even though carbon and sulfur have identical values of electronegativities, the molecule, CH_3SH is polar because of the presence of the lone pairs on the sulfur atom.

The C-S bond is not polar because the both the atoms have electronegatiivty. <u>But S has lone pairs which can attract the bond pairs of the bond between the S and H and thus acquires slightly negative charge and H acquires slightly positive charge.</u>

6 0
3 years ago
Student perfotms a Benedict's test on an unknown substance. He adds reagent(the chemical required to make a color change), and n
elixir [45]

Answer:

Reducing sugars are absent

Explanation:

Benedict's solution is an substance used in testing sugars. It is mixture of sodium carbonate, sodium citrate and copper(II) sulfate pentahydrate. It can be used instead of Fehling's solution in testing for the presence of reducing sugars.

Reducing sugars contain the -CHO group. If there is no colour change after the addition of Benedict's solution, then we can conclude that reducing sugars are absent.

7 0
3 years ago
How does peer review affect research?
Mice21 [21]

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I am pretty sure the answer is C.

Explanation:

4 0
2 years ago
Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?
Mamont248 [21]

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}.

In order to gain stability, sodium loses one electron and hence it forms a positive ion (Na^{+}).

Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.

5 0
3 years ago
Read 2 more answers
how many electrons does it take to fill the mos formed from the combination of the 3s orbitals of two atoms?
Musya8 [376]

The number of electrons it take to fill the mos formed from the combination of the 3s orbitals of two atoms simply is 14 electrons.

<h3>How electrons are distributed in the 3s orbitals.</h3>

The 3s orbital possess two different spherical nodes which is highly connected with the principal quantum number. In order words, it has 2 radial nodes. Also the shape of the 3s orbital is spherical in shape.

That being said, from the context of the above given task, the number of electrons which fill the mos formed from the combination of the 3s orbitals of two atoms is fourteen electrons.

However, the electron configuration of an atom simply is the arrangement of electrons in the electron shell or orbit of the atom of that element.

In conclusion, it can be deduced from above s orbital has a maximum of two electrons and this energy increases as the orbitals increases.

Read more on electron:

brainly.com/question/860094

#SPJ1

7 0
1 year ago
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