Answer:
(2) b, c, f
Explanation:
Hello,
In this case, for the undergoing chemical reaction:

The Gibbs free energy of reaction at 25 °C is related with an equilibrium constant of:
![K=exp(-\frac{\Delta G^0 }{RT} )=exp[-\frac{-21700J/mol}{8.314J/(mol*K)*298.15K}]=1.58x10^{-4}](https://tex.z-dn.net/?f=K%3Dexp%28-%5Cfrac%7B%5CDelta%20G%5E0%20%7D%7BRT%7D%20%29%3Dexp%5B-%5Cfrac%7B-21700J%2Fmol%7D%7B8.314J%2F%28mol%2AK%29%2A298.15K%7D%5D%3D1.58x10%5E%7B-4%7D)
Now, at the given moment, the reaction quotient turns out:

Thus, since Q<K, the reaction will have too much reactants that will produce more products, shifting the reaction rightwards to them.
Hence, with the given information the statements b, c and f are correct, so the answer is: (2) b, c, f.
Best regards.
False I hope this is right
Answer:
NaOH
Explanation:
The sodium hydroxide is strongest base because it fully dissociate into ions.
It dissociate to gives the sodium and hydroxyl ions and solution became more basic.
NaOH → Na⁺(aq) + OH⁻(aq)
Its pH is 12. It is also known as caustic soda.
Other given Options:
The pH of blood is vary from 7.35 - 7.45. it is slightly alkaline.
The pH of HCl is 3.
The pH of saliva is 6.2 - 7.6.
We know that neutral pH is 7 the pH less than 7 is acidic so HCl is acidic because its pH is 3.
The pH is greater then 7 is basic so saliva and blood are basic but less than the NaOH.
The answer should be D. A rate law needs to be rate equaling the rate constant which is represented as k (make sure you use a lower case k since an upper case K is for equilibrium) times the concentrations of each reactant raised to the power of what ever order it has. (if A was a zero order it would be [A]⁰ and if A was third order it would be [A]³).
Do not get the order the reactants are confused with the coefficients in the chemical equation. (just because the reaction has 2B does not mean the rate law will have [B]². As shown in this example since it is first order therefore being [B] in the rate law)
I hope this helps. Let me know if anything is unclear in the comments.
The atomic mass is the average of the isotopes of the element meaning most averages of isotopes will not be whole numbers