Answer:
The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g
Explanation:
Step 1: Given data
The supercritical CO2 has a density of 0.469 g/cm³ (or 0.469 g/mL)
The sample hasa volume of 25.0 mL
Step 2: Calculating mass of the sample
The density is the mass per amount of volume
0.469g/cm³ = 0.469g/ml
The mass for a sample of 25.0 mL = 0.469g/mL * 25.0 mL = 11.725g ≈ 11.7g
The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g
<em>Answer:</em>
- The concentration of new solution will be 1×10∧-7 M.
<em>Solution:</em>
<em>Data Given </em>
given mass of fluoxymesterone =16.8mg = 0.0168 g
molar mass of fluoxymesterone = 336g/mol
vol. of fluoxymesterone = 500.0 ml = 0.500 L
Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M
So applying dilution formula
Stock Solution : New Solution
M1.V1 = M2.V2
( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L
[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2
1 × 10∧-7 = M2
<em>Result:</em>
- The concentration of new solution M2 will be 1 × 10∧-7
<u>Explanation:</u>
The number of moles that are present in a liter of a solution is called Molarity. Mole is the unit of Molarity.The concentration of the solutes that are present in a solution refers to Osmolarity . The unit is osmol. This helps in observing the movement of water from one side to another side of a semipermeable membrane.
The main property of salts that helps to understand the differentiation between the molarity and osmolarity is the salts Ionization. One mole Na+ and one mole of Cl- is produced by the dissociation of a mole of sodium chloride occurs. The diffusion of water is the osmosis. Here, the one molar sodium chloride solution produces a osmotic pressure which is high than one molar glucose solution and this will not undergo dissociation.
Capillaries have very thin walls which makes it easy for them to diffuse (pass through the wall).
Answer:
a
Explanation:
because I said so and I think it's right