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goldenfox [79]
3 years ago
6

(2 points) Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas

and an aqueous solution of magnesium (II) chloride. What substance is being oxidize
Chemistry
1 answer:
julia-pushkina [17]3 years ago
3 0

<u>Answer:</u> In the given chemical equation, the substance getting oxidized is magnesium metal.

<u>Explanation:</u>

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

The chemical equation for the reaction of magnesium and hydrochloric acid follows:

Mg(s)+2HCl(aq.)\rightarrow MgCl_2(aq.)+H_2(g)

The half reaction for the above equation follows:

<u>Oxidation half reaction:</u> Mg(s)\rightarrow Mg^{+}(aq.)+2e^-

<u>Reduction half reaction:</u> 2H^+(aq.)\rightarrow H_2(g)+2e^-

Hence, in the given chemical equation, the substance getting oxidized is magnesium metal.

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How many grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline?
egoroff_w [7]

Grams of oxygen are required to react with 13.0 grams of octane (C8H18) in the combustion of octane in gasoline is 45.5g

Octane is a hydrocarbon which burns in gasoline in presence of oxygen according to the given balanced chemical equation,

2C₈H₁₈ + 25O₂------> 16CO₂ + 18H₂0

Molar mass of octane = 114.23g/mol

Molar mass of Oxygen = 32g/mol

According to the stiochiometry of the balanced equation the mole ratio of Octane and Oxygen is 2:25

2 mole of octane needs 25 mole of oxygen

1 mole of octane needs 12.5 moleof oxygen

114.23g of octane needs 400g of oxygen

13g   of octane  needs 45.5g of oxygen

Mass of oxygen needed =45.5g

Hence, the Mass of oxygen needed is 45.5g for the combustion of octane in gasoline.

Learn more about Octane here, brainly.com/question/21268869

#SPJ4

5 0
2 years ago
What is SO2 shape name?
muminat

Answer:Molecular Formula SO2

Hybridization Type sp2

Bond Angle 119o

Geometry V-Shaped or Bent

Explanation:

hope this helped <3

5 0
3 years ago
How many moles of Au2S3 is required to form 56 grams of H2S at STP?
Law Incorporation [45]

Answer:

0.55 mol Au₂S₃

Explanation:

Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.

1. Gather all the information in one place:

M_r:                          34.08

          Au₂S₃ + … ⟶ 3H₂S + …  

m/g:                             56  

2. Calculate the moles of H₂S

Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)

                      = 1.64 mol H₂S

3. Calculate the moles of Au₂S₃

The molar ratio is 1 mol Au₂S₃/3 mol H₂S.

Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)

                         = 0.55 mol Au₂S₃

7 0
3 years ago
3. Ammonia, NH3, is a typical ingredient in household cleaners. It is produced through a combination reaction involving N2(g) an
hram777 [196]
N2 + 3H2 ----> 2NH3 

<span>you can see 3 moles H2 reacts to form 2 moles NH3 </span>
<span>Therefore moles NH3 = 2 / 3 x moles H2 </span>
<span>= 2/3 x 12.0 mol </span>
<span>= 8.00 mol NH3 hope this help</span>
6 0
3 years ago
Read 2 more answers
The Russian chemist who designed the periodic table that was similar to the Periodic Table used today was _______________-
Xelga [282]
Dmitri Mendeleev, he realized that the physical and chemical properties of elements were related to their atomic mass and arranged them into groups (columns)
8 0
3 years ago
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