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2 years ago

.) Calculate the mass in grams of each of the following samples.

2 answers:

6 0

The mass in grams would be
mass= Molar mass x numbers of mole
m(C2H6O)=nM
=0.251(2x12.01+1.008x6 + 16.00)
=11.56g

Alik [6]2 years ago

4 0

12+12+6(1)+16 =46 46*.251 = 11.546 gram

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The 2 in the formula AgS is a 1. coeffcient 2. subscript 3. superscript 4. binomial

ludmilkaskok [199]

Answer:

Subscript, or B

Explanation:

AgS is the equation for the chemic reaction of Silver + Sulfur, since the subscript of 2 goes by the g in the equation, this would equal subscript.

Remember subscripts are located at the BOTTOM of a coefficient and superscripts are located at the TOP of a coefficient.

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2 years ago

The mass of an element is 27 and it's atomic number is 13. Give the composition of the nucleus of it's atom.

love history [14]

Answer:

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2 years ago

Which of the following represents the least number of molecues?

Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

$molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}$

So, let´s get the number of molecules for each of the options.

$a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules$

$b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules$

$c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules$

$d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules$

$d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules$

the smalest number is in option a)

Best of luck.

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6CO2 + 6H2O YOU JUST ADD THEM TOGETHER

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