Question

Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq)+3H2O(l) The average rate of consumption of Br− is 1.20×10−4 M/s over the first two minutes. What is the average rate of formation of Br2 during the same time interval?

Answer 1

Answer:

0.720 M/s

Explanation:

Let's consider the following balanced equation.

5Br⁻(aq) + BrO⁻₃(aq) + 6H⁺(aq) → 3 Br₂(aq) + 3H₂O(l)

The molar ratio of Br⁻ to Br₂ is 5:3, that is, when 5 moles of Br⁻ are consumed, 3 moles of Br₂ are produced. If the average rate of consumption of Br⁻ is 1.20 × 10⁻⁴ M/s, the average rate of formation of Br₂ is:

$\frac{1.20molBr^{-}}{L.s} .\frac{3molBr_{2}}{5molBr^{-}} =\frac{0.720molBr_{2}}{L.s}$