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Artemon [7]
3 years ago
15

Define an "ionic bond" using the words "give" or "take"

Chemistry
1 answer:
adelina 88 [10]3 years ago
6 0

Answer: An ionic bond is transferring or known as giving or taking valence electrons between atoms.

Explanation: By giving and taking valence electrons between atoms you can get two oppositely charged ions.

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A) ambos pertencem ao 5o período da Tabela Periódica;
Reptile [31]

Answer:

A

Explanation:

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3 years ago
Water vapor is heated and rising into the air is called what?
Lady_Fox [76]

Answer:

Evaporation

Explanation:

3 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the
Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

V_2 = \frac{P_1P_2}{P_2}  that is V₂ = \frac{1atm*1.32L}{90atm} = \frac{11}{750}L or 0.01467L

5 0
3 years ago
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Dmitriy789 [7]
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7 0
2 years ago
What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t
Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

<u>Step 1:</u> Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

<u>Step 2:</u> The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g)         ΔH°rxn = -6278 kJ

<u>Step 3:</u> Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

<u>Step 4:</u> Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

<u>Step 5:</u> Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0
2 years ago
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