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Natali [406]
4 years ago
7

which instrument is best suited for measuring the dimensions of a shoebox? a)a triple-beam balance b)a volumetric flask c)a rule

r d)a caliper
Physics
2 answers:
PilotLPTM [1.2K]4 years ago
4 0

Answer:

c a ruler

Explanation:

Aloiza [94]4 years ago
3 0
I believe the correct answer from the choices listed above is option C. The instrument that is <span>best suited for measuring the dimensions of a shoebox would be a ruler. A triple-beam balance is for measuring mass. A volumetric flask is for volume. A caliper is measuring lengths of small objects.</span>
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How did the electron change the model of the atom?
Evgesh-ka [11]
According to John Dalton, atoms are indivisible which means that they can not be broken down into smaller particles. However, J.J Thomson have proven the existence of electrons. The existence of sub-atomic particles disproved Dalton's theory. Thomson conducted his experiment using a cathode ray-tube.
4 0
3 years ago
If you do 1,000 J of work on a system and remove 500 J of heat from it, what is the change in its internal energy
DENIUS [597]
Here I advice doing thought experiment and not remembering equations. By doing thought experiment you will write down equation by yourself.

Doing some work on a system means that system will "absorb" that energy. Here, system absorbs 1000J of energy. Now you are cooling system down by removing 500J of energy. That means that system will lose 500J of energy

All of that can be written as 1000 - 500 = 500 which means that after cooling your system has 500J left.
6 0
3 years ago
Malachi uses some glue to fix a broken plate. He puts the glue under a desk lamp but the glue doesn't dry. Then he puts the glue
Semmy [17]

Answer:

The sun gives off a type of light that carries energy, and the light from the desk lamp does not

Explanation:

I got it off a Quizlet hope this helps!!

4 0
3 years ago
A certain metal with work function of Φ = 1.7 eV is illuminated in vacuum by 1.4 x 10-6 W of light with a wavelength of λ = 600
Makovka662 [10]

Answer:

1) n = 4.47*10^12 photons

2) K = 0.25 eV

Explanation:

This is a problem about the photoelectric effect.

1) In order to calculate the number of photons that impact the metal, you take into account the power of the light, which is given by:

P=\frac{E}{t}=1.4*10^{-6}\frac{J}{s}     (1)

Furthermore you calculate the energy of a photon with a wavelength of 600nm, by using the following formula:

E_p=h\frac{c}{\lambda}         (2)

c: speed of light = 3*10^8 m/s

h: Planck's constant = 6.626*10^-34 Js

λ: wavelength = 600*10^-9 m

You replace the values of the parameters in the equation (2):

E_p=(6.626*10^{-34}Js)\frac{3*10^8m/s}{600*10^{-9}m}=3.131*10^{-19}J

Next, you calculate the quotient between the power of the light (equation (1)) and the energy of the photon:

n=\frac{P}{E_p}=\frac{1.4*10^{-6}J/s}{3.131*10^{-19}J}=4.47*10^{12}photons

The number of photons is 4.47*10^12

2) The kinetic energy of the electrons emitted by the metal is given by the following formula:

K=E_p-\Phi     (3)

Ep: energy of the photons

Φ: work function of the metal = 1.7 eV

You first convert the energy of the photons to eV:

E_p=3.131*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.954eV

You replace in the equation (3):

K=1.95eV-1.7eV=0.25eV

The kinetic energy of the electrons emitted by the metal is 0.25 eV

6 0
4 years ago
Which of the following is not a function of PACs?
Katena32 [7]

Answer:

i think D

hope this helps

let me know if i'm wrong i will change the answer

Explanation:

5 0
3 years ago
Read 2 more answers
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