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Vlad [161]
3 years ago
15

The fertilizer ammonium sulfate is prepared by the reaction between ammonia and sulfuric acid.How many kg of ammonia are needed

to produce 1x10^5 kg of (NH4)2SO4?
Chemistry
1 answer:
natulia [17]3 years ago
5 0
Here is the procedure to know how to get those kg of ammonia
<span>
N<span>H3</span>+<span>H2</span>S<span>O4</span>−>(N<span>H4</span><span>)2</span>S<span>O4

</span></span><span> Molar mass of (NH4)2SO4 = (14.0 + 1.0x4)x2 + 32.1 + 16.0x4 = 132.1 No. of mole of (NH4)2SO4 =mass/ molar mass = 1x10^5 x 1000 / 132.1 = 757002.271 mole No. of mole of ammonia needed = No. of mole of (NH4)2SO4 = 757002.271 mole Mass of ammonia needed = 757002.271 x mole mass of NH3 = 757002.271 x (14.0 + 1.0x3) = 757002.271x 17.0 = 12869038.61 g = 1.29 x10^4 kg</span>
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4 0
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Which of the following sequences describe how a four stoke engine cycle powers the engine
Vera_Pavlovna [14]

A four cycle engine works with 4 basic steps to a successful rotation of the crankshaft: the intake, compression, power and exhaust stroke. Each engine cylinder has four openings for the intake, exhaust, spark plug and fuel injection. ... The compression makes the air-fuel combination volatile for easier ignition.

8 0
3 years ago
Write the concentration equilibrium constant expression for this reaction.
Akimi4 [234]

In a chemical reaction, the equilibrium constant refers to the value of its reaction quotient at chemical equilibrium, that is, a condition attained by a dynamic chemical system after adequate time has passed, and at which its composition has no measurable capacity to undergo any kind of further modification.  

The given reaction is: HCN (aq) + OH⁻ = CN⁻ (aq) + H2O (l)

The equilibrium constant = product of concentration of products / product of concentration of reactants

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8 0
3 years ago
A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
11.0 L of hydrogen and 5.52 L of oxygen are exploded together in a reaction tube. What volume of water vapor was formed, at STP?
Marysya12 [62]

Answer:

11.0 L

Explanation:

The equation for this reaction is given as;

2H2  +  O2  -->  2H2O

2 mol of H2 reacts with 1 mol of O2 to form 2 mol of H2O

At STP;

1 mol = 22.4 L

This means;

44.8 L of H2 reacts with 22.4 L of O2 to form 44.8 L of H2O

In this reaction, the limiting reactant is H2 as O2 is in excess.

The relationship between H2 and H2O;

44.8 L = 44.8 L

11.0 L would produce x

Solving for x;

x = 11 * 44.8 / 44.8

x = 11.0 L

4 0
2 years ago
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