7. 20
8. 680
9. 700
10. 4,000
11. 106,000
12. 5,800
The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.
x^3+5x^2-6x-30
(x^3+5x^2)+(-6x-30)
x^2(x+5)+(-6x-30)
x^2(x+5)-6(x+5)
(x^2-6)(x+5)
-------------
Answer: (x^2-6)(x+5)
As this is probability, we can use the next formulas and tell how is this going to be:
P(A) = student on the dean's list
<span>P(B) = student taking calculus </span>
<span>P(A n B) = 0.042 </span>
<span>P(A) = 0.21 </span>
<span>So, P(B) = 0.042/0.21 </span>
<span>= 0.2
So the probability here is of 0.2</span>
