Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).
Maybe use flash cards for them to understand or look up periodic table on line and show them.
Answer: The value of
is 2
Explanation:
Moles of
= 1.0 mole
Volume of solution = 1.00 L
Initial concentration of
= 
Equilibrium concentration of
=
The given balanced equilibrium reaction is,
Initial conc. 1.0 M 0 M
At eqm. conc. (1.0-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
Given : 2x = 1.0
x= 0.5
Now put all the given values in this expression, we get :

Thus the value of
is 2