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oee [108]
2 years ago
7

Which of these compounds would you predict

Chemistry
2 answers:
lilavasa [31]2 years ago
7 0
I think its going to be C6H14
aivan3 [116]2 years ago
3 0

Answer:c6h14

Explanation:

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The precautions that must be taken when carrying out experiments with hydrogen​
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Answer:

Never smoke near a place where hydrogen is generated or being used. Remove all possible sources of flame and sparks. Hydrogen should only be generated and used in a well ventilated out door area. Precautions must be taken to remove all possibilities of fire or explosion.

3 0
3 years ago
Balance the following equation:
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You only need a 2 at the end In front of the NaCl
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2 years ago
5. After a day of testing race cars, you decide to
kvasek [131]
Noice but I don’t get why was this necessary
8 0
3 years ago
You know that an unlabeled bottle contains an aqueous solution of one of the following: AgNO3, KCl, or (NH4)2SO4. A friend sugge
Afina-wow [57]

Answer:

These tests determine the solubility of the compounds formed upon adding the test solution

Explanation:

Addition of Ba(NO₃)₂ will cause a precipitate ((Ba)₂SO₄) to form in the solution of (NH₄)₂SO₄. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is ammonium sulfate can be determined.

Addition of NaCl solution will cause a precipitate (AgCl) to form in the solution of AgNO₃. No precipitates will form in the other unknown solutions. Thus, whether or not the solution is silver nitrate can be determined.

If no precipitates form, then the unknown solution must be KCl.

6 0
3 years ago
A student uses a calorimeter to determine the enthalpy of dissolving for ammonium nitrate. The student fills a calorimeter with
ale4655 [162]
Enthalpy change during the dissolution process = m c ΔT,

here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
                                                                                 = -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)

Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>

7 0
3 years ago
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