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igomit [66]
4 years ago
14

One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silv

er nitrate solution. Any chloride anions in solution will combine with the silver cations to produce bright white silver chloride precipitate.
Suppose an EPA chemist tests a Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin sample of groundwater known to be contaminated with nickel(II) chloride, which would react with silver nitrate solution like this:

Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin(aq) Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratinImage for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin(aq) Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratinImage for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin(s) Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratinImage for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin(aq)

The chemist adds Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratinM silver nitrate solution to the sample until silver chloride stops forming. She then washes, dries, and weighs the precipitate. She finds she has collected Image for One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titratin of silver chloride.

Calculate the concentration of nickel(II) chloride contaminant in the original groundwater sample. Round your answer to significant digits.
Chemistry
1 answer:
babunello [35]4 years ago
4 0

Answer:

5.0x10⁻⁵ M

Explanation:

It seems the question is incomplete, however this is the data that has been found in a web search:

" One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silver nitrate solution. Any chloride anions in solution will combine with the silver cations to produce bright white silver chloride precipitate. Suppose a EPA chemist tests a 250 mL sample of groundwater known to be contaminated with nickel(II) chloride, which would react with silver nitrate solution like this:

NiCl₂ + 2AgNO₃ →  2AgCl + Ni(NO₃)₂

The chemist adds 50 mM silver nitrate solution to the sample until silver chloride stops forming. She then washes, dries, and weighs the precipitate. She finds she has collected 3.6 mg of silver chloride. Calculate the concentration of nickel(II) chloride contaminant in the original groundwater sample. Round your answer to 2 significant digits. "

Keep in mind that while the process is the same, if the values in your question are different, then your answer will be different as well.

First we <u>calculate the moles of nickel chloride found in the 250 mL sample</u>:

  • 3.6 mg AgCl ÷ 143.32 mg/mmol * \frac{1mmolNiCl_{2}}{2mmolAgCl} = 0.0126 mmol NiCl₂

Now we <u>divide the moles by the volume to calculate the molarity</u>:

  • 0.0126 mmol / 250 mL = 5.0x10⁻⁵M
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marta [7]

Answer:

1) The new pressure of the gas is 500 kilopascals.

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Explanation:

1) From the Equation of State for Ideal Gases we construct the following relationship:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kPa.

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If we know that P_{1} = 100\,kPa, V_{1} = 500\,mL and V_{2} = 1000\,mL, then the new pressure of the gas is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)

P_{2} = 500\,kPa

The new pressure of the gas is 500 kilopascals.

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\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

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P_{1}, P_{2} - Initial and final pressure, measured in kPa.

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\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

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