Answer:
(a) 42 N
(b)36.7 N
Explanation:
Nomenclature
F= force test line (N)
W : fish weight (N)
Problem development
(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed
We apply Newton's first law of equlibrio because the system moves at constant speed:
∑Fy =0
F-W= 0
42N -W =0
W = 42N
(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²
We apply Newton's second law because the system moves at constant acceleration:
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
∑Fy =m*a
m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity
F-W= ( W/9.8 )*a
42-W= ( W/9.8 )*1.41
42= W+0.1439W
42=1.1439W
W= 42/1.1439
W= 36.7 N
Answer:
Only electrons
Explanation:
When a current flows through a metal wire, the moving charges are electrons since electric current is the flow of electric charge in an electric circuit. This electric charge are therefore electrons.
Answer:
Total distance = 700 m
Displacement = 500 m
Explanation:
Notice that Jed travelled a total of 3 x 100 m = 300 m in the North direction, and 300 m + 100 m = 400 m in the East direction. Therefore the total distance he travelled is: 300 + 400 = 700 m.
But the actual displacement is given by the Pythagorean theorem as the hypotenuse of a right angle triangle of legs 300 m and 400 m:
displacement = 
Answer:
λ = 3.33 m
Explanation:
<u><em>Given:</em></u>
Frequency = f = 9 × 10⁷ Hz
Speed = v = 3 × 10⁸ m/s
<u><em>Required:</em></u>
Wavelength = λ = ?
<u><em>Formula:</em></u>
v = fλ
<u><em>Solution:</em></u>
<em>Putting the givens in the formula</em>
v = fλ
λ = 
λ = 
λ = 0.33 × 10¹
λ = 3.33 m
Convection currents in the mantle
