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Goshia [24]
3 years ago
8

In some types of alcohol digestion, alcohol C_2 H_5 OHC 2 ​ H 5 ​ OHC, start subscript, 2, end subscript, H, start subscript, 5,

end subscript, O, H is broken down into vinegar, HC_2 H_3 O_2HC 2 ​ H 3 ​ O 2 ​ H, C, start subscript, 2, end subscript, H, start subscript, 3, end subscript, O, start subscript, 2, end subscript and water.
Chemistry
1 answer:
kari74 [83]3 years ago
3 0

Answer:

This is the typical route of alcohol metabolism, where in the liver it is first transformed to acetaldehyde and then to acetate.

Explanation:

Ethanol is not digested but absorbed and follows its metabolic pathway in the liver, producing in the first instance acetaldehyde, which is the main substance that causes the hangover and then this compound is transformed into the final product, which is acetate Later acetate is metabolized to Acetyl-CoA. The enzyme responsible for the metabolism of ethanol is alcohol dehydrogenase in the liver, and for the cytochrome P-450 dependent system and for catalase in the liver.

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Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

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