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3 years ago

What is an atomic nucleus

Physics

2 answers:

Agata [3.3K]3 years ago

8 0

Answer:

The atomic nucleus is the small, dense region consisting of protons and [[]]s at the center of an atom

Explanation:

DENIUS [597]3 years ago

7 0

The small dense region consisting of protons and neutrons at the center of an atom

You might be interested in

A. What quantum number of the hydrogen atom comes closest to giving a 61-nm-diameter electron orbit?

Black_prince [1.1K]

Answer:

$n = 23$

$v = 87377.95 \ m/s$

Explanation:

From the question we are told that

The diameter is $d = 61\ nm = 61 *10^{-9} \ m$

Generally the radius electron orbit is mathematically represented as

$r = \frac{61 *10^{-9}}{2}$

=> $r = 3.05*10^{-8} \ m$

This radius can also be represented mathematically as

$r = n^2 * a_o$

Here n is the quantum number and $a_o$ is the Bohr radius with a value

$a_o = 0.0529 *10^{-9} \ m$

$n = \sqrt{\frac{3.05*10^{-8}}{ 0.059*10^{-9}} }$

=> $n = 23$

Generally the angular momentum of the electron is mathematically represented as

$L = m * v * r = \frac{n * h }{2 \pi}$

Here h is the Planck constant and the value is $h = 6.626*10^{-34} J \cdot s$

m is the mass of the electron with values $m = 9.1*10^{-31} \ kg$

$v = \frac{23 * 6.626*10^{-34} }{2\pi * 9.1 *10^{-31} * 3.05*10^{-8} }$

$v = 87377.95 \ m/s$

3 0

3 years ago

The speed of an object undergoing constant acceleration increased from 8.0 meters per second to 16.0 meters per second in 10. Se

saw5 [17]

v₀ = initial speed of the object = 8 meter/second

v = final speed of the object = 16 meter/second

t = time taken to increase the speed = 10 seconds

d = distance traveled by the object in the given time duration = ?

using the kinematics equation

d = (v + v₀) t/2

inserting the above values in the above equation

d = (16 + 8) (10)/2

d = 120 meter

6 0

3 years ago

A track begins at 0 meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing for a rac

shusha [124]

Answer : The correct option is (D).

Explanation :

Given that,

A track begins at 0 meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing for a race.

We have to find her position after she runs 45 meters.

From the attached figure,

Let A is the position of Juliet. O is the initial point such that OA = 10 m, AB = 45 m and OP = 100 m.

So, using simple mathematics, it is clear that the position of Juliet after running 45 meters will be 55 m. It is OB in the figure.

So, the correct option is (D) " 55 meters ".

3 0

3 years ago

Read 2 more answers

Realiza la siguiente conversión de unidades: 340 N a Kgf

OleMash [197]

Answer:

The answer is 34.67 kilograms force

3 0

3 years ago

A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is

Umnica [9.8K]

The frequency of note C3 is 131 $s^{-1}$ .

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

$Frequency=\frac{speed of sound}{Wavelength of note}$

Thus,

$Frequency = \frac{343 m/s}{2.62 m} = 131 s^{-1}$

So the frequency of note C3 is 131 $s^{-1}$ .

3 0

3 years ago