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3 years ago

The floor at a roller-skating rink is 72.25 feet long and 51.5 feet wide. How much longer is the rink than it is wide?

Mathematics

2 answers:

umka2103 [35]3 years ago

8 0

The rink's length is 20.75 feet
longer than it is wide

stellarik [79]3 years ago

5 0

The answer to this question is 20.75 and your welcome

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3n+8=20 i need help i think it is algerbra

tia_tia [17]

turn the problem around

20-8=12

12/3=4

Your answer is 4.

4 0

3 years ago

Read 2 more answers

There is a L-shaped sidewalk that is 158 meters long. By cutting across the lawn, the

NikAS [45]

Answer:

Each side of the L-shaped sidewalk is 126 m and 32m respectively.

Step-by-step explanation:

Given:

Total length of the sidewalk = 158 meters

Cutting across the lawn the distance = 130 meters

The L-shaped lawn will be treated as a right angled triangle.

So the 130 m distance is the hypotenuse here.

Let one side of the L-shaped lawn be 'x' meter so the another side will be (158-x) meters.

Applying Pythagoras formula.

$(Hypotenuse)^2=(height)^2+(base)^2$

So,

⇒ $(130)^2=x^2 +(158-x)^2$

⇒ $(130)^2=x^2+(158-x)(158-x)$

⇒ $16900=x^2+24964-158x-158x+x^2$

⇒ $16900 =2x^2-316x+24964$

⇒ $2x^2+316x+24964-16900=0$

⇒ $2x^2-316x+8064=0$

⇒ $x^2-158x+4032=0$

Applying quadratic formula;

Quadratic formula : $\frac{\pm b \sqrt{b^2-4ac} }{2a}$ where a=1 and b=-158 and c=4032

So the value of x= 126 and 32.

The length of each side of the sidewalk is 'x'= 126 m and '(158-x)'='(158-126)'=32 m

7 0

3 years ago

When graphing y = 2x2 + 35x + 75, which viewing window would allow you to see all of the intercepts and the minimum as closely a

djverab [1.8K]

The intercept with the y-axes occurs when x = 0

f(0) = 2*02 + 35*0 + 75 = 0 + 0 + 75 = 75

So intercept with x axes is the point (0,75)

The intercept with the x-axes occurs when y=0

2x2 + 35x + 75 = 0

As there’s no direct way to find x, we can use the Bhaskara formula:

x=(-b+- square root (b2-4ac))/(2a)

This formula is for: ax2 +bx + c = 0

So:

a=2

b=35

c=75

x=(-35+- square root (35^2-4*2*75))/(2*2)

So x can be -2.5 or -15

So intercept with y axes are the points (-2.5,0) and (-15,0)

And there is also a formula to find the mínimum. The mínimum is always the vertex:

Xv = -b/(2*a) = -35/(2*2) = -8.75

Yv = f(Xv) = f(-8.75) = 2(-8.75)^2 + 35(-8.75) + 75 = -78.125

So the minimum is the point (-8.75, -78.125)

You can easily verify all these data with a graphic software such as GeoGebra.

Here is the complete list of all the points we need to see:

(0,75); (-2.5,0) ; (-15,0), (-8.75, -78.125)

So the mínimum X has to be -15 and the máximum X has to be 0

and the mínimum Y has to be -78.125 and the máximum Y has to be 75

So this leads to a different scale for X and for Y.

Window x = [ -15, 0] y = [ -78.125, 75]

5 0

3 years ago

What is 43.09 to the nearest whole number

Svetach [21]

Answer:

Step-by-step explanation:

43.09 has 2 parts the integer part which is basically to the left and the decimal point which is to the right. to get this to the nearest integer or whole number you would have to round it off so you only have the integer part to do so the first digit in the fractional part is less than 5 then simply remove the fractional part to get the answer but in this case the de

6 0

2 years ago

Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day. The

faltersainse [42]

Answer:

30units,2900

Step-by-step explanation:

Given that Country Motorbikes Incorporated finds that it costs $400 to produce each motorbike, and that fixed costs are $1600 per day.

The price function is p(x) = 700 − 5x, where p is the price (in dollars) at which exactly x motorbikes will be sold.

If x units are produced and sold we have

Costs for x units = variable costs *x +Fixed costs $= 400x+1600$