Answer: You do not specify what is being asked for. ∆E? ∆H?
∆E = (430 - 238) J = 192 J
∆H = 430 J
Explanation:
If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.
Therefore ∆H = 430 J
If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w
The question states that 238 J of work are done AND the system expanded
(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)
Therefore, ∆E = (430 - 238) J = 192 J
Answer:
Explanation:
Calculating the exit temperature for K = 1.4
The value of
is determined via the expression:

where ;
R = universal gas constant = 
k = constant = 1.4


The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :
------ equation(1)
we can rewrite the above equation as :


where:



Thus, the exit temperature = 402.36 K
The exit pressure is determined by using the relation:



Therefore, the exit pressure is 17.79 bar
Answer: s=d/t= 500/7.0=71.42 m/s
Explanation:
Protons
electrons are negatively charged
neutrons are neutral