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sp2606 [1]
3 years ago
14

Two astronauts push on a satellite. One pushes in the positive x direction with a force of 42 N, and the other pushes in the pos

itive y direction. If the net force is at an angle of 15° above the positive x axis, what is the magnitude of the second astronaut's force?
Physics
1 answer:
inessss [21]3 years ago
4 0

The vectors adition we can find the magnitude of the force applied by the other astronaut is  11.25 N in the y direction

 

Parameters given

  • Force of an astronaut Fₓ = 42 N
  • Angle θ = 15º

To find

  • Force another astronaut

The force is a vector magnitude for which the addition of vectors must be used, a very efficient method to perform this sum is to add the components of each vector and devise constructing the resulting vector using trigonometry and the Pythagorean theorem.

Let's use trigonometry to find the other force

            tan θ = \frac{F_y}{F_x}

            F_ y = Fₓ tan θ

let's calculate

            F_y = 42 tan 15

            F_y = 11.25 N

Using the summation of vectors we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction

Learn more about vector addition here:

brainly.com/question/15074838

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two forces whose magnitude are in ratio of 3:5 gives a resultant of 35N.if the angle of inclination is 60degree.calculate the ma
nadya68 [22]

Answer:

the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

Explanation:

The computation of the magnitude of the each force is shown below:

Provided that

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Let us assume the common factor is x

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Resultant force = 35 N

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Based on the above information

Resultant force i.e. F = √ F_1^2 +F_2^2 + 2 F_1F_2cos\theta

35 = √[(3x)²+ (5x)²+ 2 (3x)(5x) cos 60°]

 35 =√ 9x² + 25x² + 15x²    (cos 60° = 0.5)

35 = √49 x²

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So, the magnitude of first force = 3 × 5= 15 N

ANd, the magnitude of second force = 5 × 5 = 25 N

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